Is it possible to switch rows and columns in a datagridview?

Question

I have 10 records of data in a DataTable which has 3 fields \"Foo\", \"Bar\", and \"Baz\".

If I connect wire this into a DataGridView I see 10 rows and 3 columns, an

Answer 1

Apply a LayoutTransform to the DataGrid:

<DataGrid Name = "reverseThis">
    <DataGrid.Columns>
        <DataGridTextColumn Header="Top" Binding="{Binding Path=Top}"/>
        <DataGridTextColumn Header="Middle" Binding="{Binding Path=Middle}"/>
        <DataGridTextColumn Header="Bottom" Binding="{Binding Path=Bottom}"/>
    </DataGrid.Columns>
    <DataGrid.LayoutTransform>
        <TransformGroup>
            <RotateTransform Angle="-90"/>
            <ScaleTransform ScaleX="1" ScaleY="-1" />
        </TransformGroup>
    </DataGrid.LayoutTransform>

You also need to reverse the column headers:

<DataGrid.ColumnHeaderStyle>
    <Style TargetType="{x:Type DataGridColumnHeader}"
                                   BasedOn="{StaticResource {x:Type DataGridColumnHeader}}">
        <Setter Property="LayoutTransform">
            <Setter.Value>
                <TransformGroup>
                    <RotateTransform Angle="-90"/>
                    <ScaleTransform ScaleX="1" ScaleY="-1" />
                </TransformGroup>
            </Setter.Value>
        </Setter>
        <Setter Property="FontWeight" Value="Bold"></Setter>
    </Style>
</DataGrid.ColumnHeaderStyle>

and the cells, otherwise they come out mirrored and rotated:

    <DataGrid.CellStyle>
        <Style TargetType="DataGridCell" >
            <Setter Property="LayoutTransform">
                <Setter.Value>
                    <TransformGroup>
                        <RotateTransform Angle="-90"/>
                        <ScaleTransform ScaleX="1" ScaleY="-1" />
                    </TransformGroup>
                </Setter.Value>
            </Setter>
        </Style>
    </DataGrid.CellStyle>

</DataGrid>

Answer 2

You can create new DataTable, add appropriate number of collumns and then copy values from one table to the other, just swap rows and colums.

I don't think you can set row header in the same way you can set column header (or at least I don't know how), so you can put the field names in separate colum.

DataTable oldTable = new DataTable();

...

DataTable newTable = new DataTable();

newTable.Columns.Add("Field Name");
for (int i = 0; i < oldTable.Rows.Count; i++)
    newTable.Columns.Add();

for (int i = 0; i < oldTable.Columns.Count; i++)
{
    DataRow newRow = newTable.NewRow();

    newRow[0] = oldTable.Columns[i].Caption;
    for (int j = 0; j < oldTable.Rows.Count; j++)
        newRow[j+1] = oldTable.Rows[j][i];
    newTable.Rows.Add(newRow);
}

dataGridView.DataSource = newTable;

Answer 3

I use the Developer Expres Vertical Grid.. It is like you want a rotated grid. It also allows for a different editor per row.

Link to vertical grid product page

Answer 4

You can do this by programmatically adding the number of columns you need (e.g., 7 more to make 10) then programmatically swapping row, col with col, row.

Answer 5

In my case needed also to add a name to all columns of the new table. I wrote a function to generate a transposed table like this:

static public DataTable Transpose(DataTable inputTable, List<string> newColumnNames)
{
    DataTable outputTable = new DataTable();

    ///You should also verify if newColumnsNames.Count matches inputTable number of row

    //Creates the columns, using the provided column names.
    foreach (var newColumnName in newColumnNames)
    {
        outputTable.Columns.Add(newColumnName, typeof(string));
    }

    foreach (DataColumn inputColumn in inputTable.Columns)
    {
        //For each old column we generate a row in the new table
        DataRow newRow = outputTable.NewRow();

        //Looks in the former header row to fill in the first column
        newRow[0] = inputColumn.ColumnName.ToString();

        int counter = 1;
        foreach (DataRow row in inputTable.Rows)
        {
            newRow[counter] = row[inputColumn.ColumnName].ToString();
            counter++;
        }
        outputTable.Rows.Add(newRow);
    }

    return outputTable;

}