Extract numbers from a text in SQL Server

Question

i was searching script to extract number from text in sql server and i found this

CREATE FUNCTION [dbo].[GetNumbersFromText](@String VARCHAR(2000))
RETURNS @         


        

Answer 1

Here is an appropriate and working solution for this query

http://www.ittutorials.in/source/sql/sql-function-to-extract-only-numbers-from-string.aspx

Answer 2

@Vikram's basic idea is not bad, but their query would return all the numbers as a single item. The following function returns a table containing separate numbers as found in the source string:

CREATE FUNCTION dbo.GetNumbersFromText (@String varchar(2000))
RETURNS TABLE
AS
RETURN (
  WITH NumbersSplit AS (
    SELECT
      C = SUBSTRING(@String, number, 1),
      i = number,
      g = number - ROW_NUMBER() OVER (ORDER BY number)
    FROM master..spt_values
    WHERE type = 'P'
      AND SUBSTRING(@String, number, 1) BETWEEN '0' AND '9'
  ),
  NumbersAssembled AS (
    SELECT
      number = CAST(
        (SELECT C + '' FROM NumbersSplit WHERE g = g.g ORDER BY i FOR XML PATH (''))
        AS varchar(2000)
      )
    FROM NumbersSplit g
    GROUP BY g
  )
  SELECT * FROM NumbersAssembled
)

Note: this solution would work in SQL Server 2005 or later.

Answer 3

This is a bit shorter. Turned it into Inline Table Function that uses a recursive CTE to find the numbers.

create function [dbo].[GetNumbersFromText](@String varchar(2000))
returns table as return
(
  with C as
  (
    select cast(substring(S.Value, S1.Pos, S2.L) as int) as Number,
           stuff(s.Value, 1, S1.Pos + S2.L, '') as Value
    from (select @String+' ') as S(Value)
      cross apply (select patindex('%[0-9]%', S.Value)) as S1(Pos)
      cross apply (select patindex('%[^0-9]%', stuff(S.Value, 1, S1.Pos, ''))) as S2(L)
    union all
    select cast(substring(S.Value, S1.Pos, S2.L) as int),
           stuff(S.Value, 1, S1.Pos + S2.L, '')
    from C as S
      cross apply (select patindex('%[0-9]%', S.Value)) as S1(Pos)
      cross apply (select patindex('%[^0-9]%', stuff(S.Value, 1, S1.Pos, ''))) as S2(L)
    where patindex('%[0-9]%', S.Value) > 0
  )
  select Number
  from C
)

If you expect to have more than 100 numbers in the string you need to call it with option (maxrecursion 0).

declare @S varchar(max)
set @S = 'Give me 120 this week and 50 next week'
select number from GetNumbersFromText(@S) option (maxrecursion 0)

Answer 4

-- Try This Code... -- Its OK!!!

---

CREATE FUNCTION [dbo].[udf_ExtractNumberFromString]
(
    @pInputString VARCHAR(MAX)
)
RETURNS VARCHAR(MAX)
AS
BEGIN

    DECLARE @OutputString varchar(MAX)=''
    DECLARE @string varchar(MAX)
    DECLARE @start INT
    DECLARE @end INT
    DECLARE @len INT

    SET @string=@pInputString
    --SET @string = 'the22478ddffafghrty12345TestAddressdd5aa789324-#345'
    SET @string = replace(@string, ' ' , '')

    WHILE PATINDEX('%[0-9]%',@string) <> 0
    BEGIN   
        SET @len = len(@string)
    --  PRINT @len

        set @start = PATINDEX('%[0-9]%',@string)
    --  PRINT @start

        SET @end= PATINDEX('%[^0-9]%',SUBSTRING(@string,@start,@len-@start))
    --  PRINT @end

        IF @end=0
            BEGIN
                SET @end=@len-@start
                SET @OutputString=SUBSTRING(@string,@start,@end+1)+'-'+@OutputString
                BREAK
            END
        ELSE 
            BEGIN 
                SET @OutputString=SUBSTRING(@string,@start,@end-1)+'-'+@OutputString
                SET @string=SUBSTRING(@string,@end+@start-1,@len-@end)
            END 

        --PRINT @string

        --PRINT @Output
        --PRINT '---------------------'
    END

    IF LEN(@OutputString)>0
        SET @OutputString=LEFT(@OutputString,LEN(@OutputString)-1) 
    --PRINT @OutputString

    RETURN @OutputString
END

Answer 5

try the following logic:

declare @thestring varchar(50) 
set @thestring = 'Give me 120 this week and 50 next week' 
declare @final varchar(50) 
set @final = '' 

select @final = @final + x.thenum 
from 
( 
    select substring(@thestring, number, 1) as thenum, number 
    from master..spt_values 
    where substring(@thestring, number, 1) like '[0-9]' and type='P'
) x 
order by x.number 

print @final