How can I determine if I should extend one of my interfaces with IDisposable or implement IDisposable on a class that implements my interface?
I have an interface th
If you expect callers to only be able to interact with the interface, and never the implementation, then you want to have the interface extend IDisposable
. If not, they'll need to check if the value is IDisposable
anyway to see if it needs to be disposed.
If the object responsible for disposing of the object knows of the concrete implementation, and it is only ever objects that are given references to it (but aren't responsible for disposing of it) that use the interface, then consider the second option.
A good example of the first option is IEnumerator
. Many IEnumerator
objects don't need to do anything when they're disposed, but some do, and so the interface extends IDisposable
because the object responsible for the creation/lifecycle of that object will (or should) never have knowledge of the underlying implementation.
An example of the second would be something like IComparer
many objects that need to be compared are disposable, but the sections of code using an object through the interface aren't responsible for it's creation/lifecycle, so it needs no knowledge of whether or not that type is disposable.
The $50,000 question is whether responsibility of disposal will ever be passed along with the interface or, to put it another way, whether the last entity to use an implementing object might be something other than the entity which creates it.
The big reason that IEnumerator<T>
implements IDisposable
is that implementing objects are created by objects that implement IEnumerable<T>.GetEnumerator()
but are then generally used by other objects. The object that implements IEnumerable<T>
will know whether the thing it returns really needs disposing, but will have no way of knowing when the recipient is done with it. The code that calls IEnumerable<T>.GetEnumerator()
will know when it's done with the returned object, but will have no way of knowing whether it needs any cleanup. The sensible thing to do is specify that the code which calls IEnumerable<T>.GetEnumerator()
is required to ensure that the returned object will have Dispose
called on it before it is abandoned; the Dispose
method will in many cases not do anything, but unconditionally calling a do-nothing method which is guaranteed to exist is cheaper than checking for the existence of a method that does not exist.
If the nature of your interface type is such that the the questions of whether an implementing object needs cleanup and when such cleanup should occur will both be answerable by the same entity, then there's no need for the interface to inherit IDisposable
. If instances will be created by one entity but last used by another, then inheriting IDisposable
would be wise.
If you implement IDisposable
on the concrete class and the interface users know that it might be Disposable; you can do
IFoo foo = Factory.Create("type");
using(foo as IDisposable){
foo.bar();
}
If foo
does not implement IDisposable
, the using
will amount to using(null)
which will work just fine.
The output of the below sample program will be
Fizz.Bar
Fizz.Dispose
Buzz.Bar
Sample program
using System;
internal interface IFoo
{
void Bar();
}
internal class Fizz : IFoo, IDisposable
{
public void Dispose()
{
Console.WriteLine("Fizz.Dispose");
}
public void Bar()
{
Console.WriteLine("Fizz.Bar");
}
}
internal class Buzz : IFoo
{
public void Bar()
{
Console.WriteLine("Buzz.Bar");
}
}
internal static class Factory
{
public static IFoo Create(string type)
{
switch (type)
{
case "fizz":
return new Fizz();
case "buzz":
return new Buzz();
}
return null;
}
}
public class Program
{
public static void Main(string[] args)
{
IFoo fizz = Factory.Create("fizz");
IFoo buzz = Factory.Create("buzz");
using (fizz as IDisposable)
{
fizz.Bar();
}
using (buzz as IDisposable)
{
buzz.Bar();
}
Console.ReadLine();
}
}