The problem is your query returned false meaning there was an error in your query. After your query you could do the following:
if (!$result) {
die(mysqli_error($link));
}
Or you could combine it with your query:
$results = mysqli_query($link, $query) or die(mysqli_error($link));
That will print out your error.
Also... you need to sanitize your input. You can't just take user input and put that into a query. Try this:
$query = "SELECT * FROM shopsy_db WHERE name LIKE '%" . mysqli_real_escape_string($link, $searchTerm) . "%'";
In reply to: Table 'sookehhh_shopsy_db.sookehhh_shopsy_db' doesn't exist
Are you sure the table name is sookehhh_shopsy_db? maybe it's really like users or something.
