Naming Loops in Python

Question

I recently read this question which had a solution about labeling loops in Java.

I am wondering if such a loop-naming system exists in Python. I have been in a situa

Answer 1

There was a proposal to include named loops in python PEP3136, however, it was rejected with an explanation here. The rejection was mostly due to the rare number of circumstances where code readability would be improved by including this construct.

Answer 2

Though there are reasons to include named looped in language construct you can easily avoid it in python without loss of readability. An implementation of the referred example in python

>>> try:
    for i in xrange(0,5):
        for j in xrange(0,6):
            if i*j > 6:
                print "Breaking"
                raise StopIteration
            print i," ",j
except StopIteration:
    print "Done"


0   0
0   1
0   2
0   3
0   4
0   5
1   0
1   1
1   2
1   3
1   4
1   5
2   0
2   1
2   2
2   3
Breaking
Done
>>> 

I solve this problem by putting the inner loop in a function that returns (among others) a boolean which is used as a breaking condition.

I think you should try this. This is very pythonic, simple and readable.

Answer 3

Nope.

Depending on what you are doing, there is good chance you can use something from itertools to flatten your nested for loops into a single for loop.

Answer 4

Here's a way to break out of multiple, nested blocks using a context manager:

import contextlib

@contextlib.contextmanager
def escapable():
    class Escape(RuntimeError): pass
    class Unblock(object):
        def escape(self):
            raise Escape()

    try:
        yield Unblock()
    except Escape:
        pass

You can use it to break out of multiple loops:

with escapable() as a:
    for i in xrange(30):
        for j in xrange(30):
            if i * j > 6:
                a.escape()

And you can even nest them:

with escapable() as a:
    for i in xrange(30):
        with escapable() as b:
            for j in xrange(30):
                if i * j == 12:
                    b.escape()  # Break partway out
                if i * j == 40:
                    a.escape()  # Break all the way out