Is it possible to declare the type of the variable in Rust for loops?

Question

C++ example:

for (long i = 0; i < 101; i++) {
    //...
}

In Rust I tried:

for i: i64 in 1..100 {
    // ...
}
         


        

Answer 1

No, it is not possible to declare the type of the variable in a for loop.

Instead, a more general approach (e.g. applicable also to enumerate()) is to introduce a let binding by destructuring the item inside the body of the loop.

Example:

for e in bytes.iter().enumerate() {
    let (i, &item): (usize, &u8) = e; // here
    if item == b' ' {
        return i;
    }
}

Answer 2

You can use an integer suffix on one of the literals you've used in the range. Type inference will do the rest:

for i in 1i64..101 {
    println!("{}", i);
}

Answer 3

If your loop variable happens to be the result of a function call that returns a generic type:

let input = ["1", "two", "3"];
for v in input.iter().map(|x| x.parse()) {
    println!("{:?}", v);
}

error[E0284]: type annotations required: cannot resolve `<_ as std::str::FromStr>::Err == _`
 --> src/main.rs:3:37
  |
3 |     for v in input.iter().map(|x| x.parse()) {
  |                                     ^^^^^

You can use a turbofish to specify the types:

for v in input.iter().map(|x| x.parse::<i32>()) {
//                                   ^^^^^^^
    println!("{:?}", v);
}

Or you can use the fully-qualified syntax:

for v in input.iter().map(|x| <i32 as std::str::FromStr>::from_str(x)) {
//                            ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
    println!("{:?}", v);
}

See also:

• How do I imply the type of the value when there are no type parameters or ascriptions?