I havent found much of the topic of creating a password protected Excel file using Python.
In Openpyxl, I did find a SheetProtection
module using:
Looking at the docs for openpyxl
, I noticed there is indeed a openpyxl.worksheet.SheetProtection
class. However, it seems to be already part of a worksheet object:
>>> wb = Workbook()
>>> ws = wb.worksheets[0]
>>> ws.protection
<openpyxl.worksheet.protection.SheetProtection object at 0xM3M0RY>
Checking dir(ws.protection)
shows there is a method set_password
that when called with a string argument does indeed seem to set a protected flag.
>>> ws.protection.set_password('test')
>>> wb.save('random.xlsx')
I opened random.xlsx
in LibreOffice and the sheet was indeed protected. However, I only needed to toggle an option to turn off protection, and not enter any password, so I might be doing it wrong still...
openpyxl is unlikely ever to provide workbook encryption. However, you can add this yourself because Excel files (xlsx format version >= 2010) are zip-archives: create a file in openpyxl and add a password to it using standard utilities.
Here's a workaround I use. It generates a VBS script and calls it from within your python script.
def set_password(excel_file_path, pw):
from pathlib import Path
excel_file_path = Path(excel_file_path)
vbs_script = \
f"""' Save with password required upon opening
Set excel_object = CreateObject("Excel.Application")
Set workbook = excel_object.Workbooks.Open("{excel_file_path}")
excel_object.DisplayAlerts = False
excel_object.Visible = False
workbook.SaveAs "{excel_file_path}",, "{pw}"
excel_object.Application.Quit
"""
# write
vbs_script_path = excel_file_path.parent.joinpath("set_pw.vbs")
with open(vbs_script_path, "w") as file:
file.write(vbs_script)
#execute
subprocess.call(['cscript.exe', str(vbs_script_path)])
# remove
vbs_script_path.unlink()
return None