When I use % operator on float values I get error stating that \"invalid operands to binary % (have ‘float’ and ‘double’)\".I want to enter the integers value only but the n
The %
operator is only defined for integer type operands; you'll need to use the fmod*
library functions for floating-point types:
#include <math.h>
double fmod(double x, double y);
float fmodf(float x, float y);
long double fmodl(long double x, long double y);
If you want to use an int use long long, don't use a format that is non-ideal for your problem if a better format exists.
You can use the fmod function from the standard math library. Its prototype is in the standard header <math.h>
.
You're probably better off using long long
, which has greater precision than double
in most systems.
Note: If your numbers are bigger than a long long
can hold, then fmod
probably won't behave the way you want it to. In that case, your best bet is a bigint library, such as this one.
consider : int 32 bit and long long int of 64 bits
Yes, %(modulo) operator isn't work with floats and double.. if you want to do the modulo operation on large number you can check long long int(64bits)
might this help you.
still the range grater than 64 bits then in that case you need to store the data in .. string and do the modulo operation algorithmically.
or either you can go to any scripting language like python
When I haven't had easy access to fmod
or other libraries (for example, doing a quick Arduino sketch), I find that the following works well enough:
float someValue = 0.0;
// later...
// Since someValue = (someValue + 1) % 256 won't work for floats...
someValue += 1.0; // (or whatever increment you want to use)
while (someValue >= 256.0){
someValue -= 256.0;
}