Cannot find the file specified when using subprocess.call('dir', shell=True) in Python

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北海茫月
北海茫月 2020-12-03 13:59

In a 64-bit system with 32 bit python 2.7 installed I am trying to do the following:

import subprocess
p = subprocess.call(\'dir\', shell=True)
print p


        
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4条回答
  • 2020-12-03 14:31

    Before downvote, note that the question was edited after i posted this answer.

    I think os.listdir is more suitable for your case:

    >>> import os
    >>> os.listdir()
    ['1.txt', '2.txt', '3.txt', 'DLLs', 'Doc', 'e.txt', 'include', 'Lib', 'libs', 'LICENSE.txt', 'm.txt', 'msvcr100.dll', 'NEWS.txt', 'py.exe', 'python.exe', 'python33.dll', 'pythonw.exe', 'pyw.exe', 'README.txt', 'Scripts', 't.txt', 'tcl', 'Tools']
    

    If you want to run it in the command line itself, and just feeling like to call it, you can use os.sytem:

    os.system('dir')
    

    This will run the commmand, but it returns 0 and you can't store it.

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  • 2020-12-03 14:37

    use Shell= True, It's working for me.

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  • 2020-12-03 14:39

    In case anyone else besides me doesn't see this in the (3.4) docs right away:

    On Windows with shell=True, the COMSPEC environment variable specifies the default shell. The only time you need to specify shell=True on Windows is when the command you wish to execute is built into the shell (e.g. dir or copy). You do not need shell=True to run a batch file or console-based executable.

    Note Read the Security Considerations section before using shell=True.

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  • 2020-12-03 14:41

    I think you may have a problem with your COMSPEC environment variable:

    >>> import os
    >>> os.environ['COMSPEC']
    'C:\\Windows\\system32\\cmd.exe'
    >>> import subprocess
    >>> subprocess.call('dir', shell=True)
    
        (normal output here)
    
    >>> os.environ['COMSPEC'] = 'C:\\nonexistent.exe'
    >>> subprocess.call('dir', shell=True)
    Traceback (most recent call last):
      File "<stdin>", line 1, in <module>
      File "c:\Python27\lib\subprocess.py", line 493, in call
        return Popen(*popenargs, **kwargs).wait()
      File "c:\Python27\lib\subprocess.py", line 679, in __init__
        errread, errwrite)
      File "c:\Python27\lib\subprocess.py", line 896, in _execute_child
        startupinfo)
    WindowsError: [Error 2] The system cannot find the file specified
    

    I discovered this potential issue by digging into subprocess.py and looking in the _execute_child function, as pointed-to by the traceback. There, you'll find a block starting with if shell: that will search the environment for said variable and use it to create the arguments used to launch the process.

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