Using named parameters with PDO for LIKE

Question

I am trying to search the name field in my database using LIKE. If I craft the SQL \'by hand` like this:

$query = \"SELECT * \\n\"
         


        

Answer 1

The bound :placeholders are not to be enclosed in single quotes. That way they won't get interpreted, but treated as raw strings.

When you want to use one as LIKE pattern, then pass the % together with the value:

$query = "SELECT * 
          FROM `help_article` 
          WHERE `name` LIKE :term ";

$sql->execute(array(":term" => "%" . $_GET["search"] . "%"));

Oh, and actually you need to clean the input string here first (addcslashes). If the user supplies any extraneous % chars within the parameter, then they become part of the LIKE match pattern. Remember that the whole of the :term parameter is passed as string value, and all %s within that string become placeholders for the LIKE clause.