ORACLE SQL:Get all integers between two numbers

Question

Is there any way to select the numbers (integers) that are included between two numbers with SQL in Oracle; I don\'t want to create PL/SQL procedure or function.

Fo

Answer 1

Gary, to show the result that he explained, the model query will be:

SELECT c1 FROM DUAL MODEL DIMENSION BY (1 as rn)
MEASURES (1 as c1) RULES ITERATE (8) (c1[ITERATION_NUMBER]=ITERATION_NUMBER+3) ORDER BY rn

;)

I always use:

SELECT (LEVEL - 1) + 3 as result FROM Dual CONNECT BY Level <= 8

Where 3 is the start number and 8 is the number of "iterations".

Answer 2

I want to share an usefull query that converts a string of comma and '-' separated list of numbers into a the equivalent expanded list of numbers:

An example that converts '1,2,3,50-60' into

1
2
3
50
51
...
60

select distinct * from (SELECT (LEVEL - 1) + mini as result FROM (select REGEXP_SUBSTR (value, '[^-]+', 1, 1)mini ,nvl(REGEXP_SUBSTR (value, '[^-]+', 1, 2),0) maxi from (select REGEXP_SUBSTR (value, '[^,]+', 1, level) as value from (select '1,2,3,50-60' value from dual) connect by level <= length(regexp_replace(value,'[^,]*'))+1)) CONNECT BY Level <= (maxi-mini+1)) order by 1 asc;

You may use it as a view and parametrize the '1,2,3,50-60' string

Answer 3

create table numbers (value number);

declare
    x number;
begin
    for x in 7 .. 25
    loop
        insert into numbers values (x);
    end loop;
end;
/

Answer 4

This trick with Oracle's DUAL table also works:

SQL> select n from
  2  ( select rownum n from dual connect by level <= 10)
  3  where n >= 3;

         N
----------
         3
         4
         5
         6
         7
         8
         9
        10

Answer 5

In addition to the answers already provided, it is possible to combine the listagg function with connect by to obtain the result in the format mentioned in the question. See a code example below:

SELECT 
   DBMS_LOB.SUBSTR(LISTAGG(S.INTEGERS,',' ) WITHIN GROUP (ORDER BY S.INTEGERS), 300,1) RESULT 
FROM 
   (SELECT 
      INTEGERS 
   FROM 
      ( SELECT ROWNUM INTEGERS FROM DUAL CONNECT BY LEVEL <= 10) 
   WHERE 
      INTEGERS >= 3 
   ) S;

OutPut:

SQL> 
RESULT
----------------
3,4,5,6,7,8,9,10

Answer 6

I just did a table valued function to do this in SQL server, if anyone is interested, this works flawlessly.

CREATE FUNCTION [dbo].[NumbersBetween]
(
    @StartN int,
    @EndN int
)
RETURNS 
@NumberList table
(
    Number int
)

AS

BEGIN

WHILE @StartN <= @EndN
    BEGIN
    insert into @NumberList
    VALUES (@StartN)
    set @StartN = @StartN + 1
    END

Return

END
GO

If you run the query: "select * from dbo.NumbersBetween(1,5)" (w/o the quotes of course) the result will be

Number
-------
1
2
3
4
5