Passing an instance method as argument in PHP

Question

I would like to create a Listener class

class Listener {
    var $listeners = array();
    
    public function add(callable $function) {
        $this->li         


        

Answer 1

• Before PHP 5.4, there was no type named callable, so if you use it as a type hint, it means "the class named callable". If you use PHP >= 5.4, callable is a valid hint.

• A callable is specified by a string describing the name of the callable (a function name or a class method name for example) or an array where the first element is an instance of an object and the second element is the name of the method to be called.

For PHP < 5.4, replace

public function add(callable $function)

with:

public function add($function)

Call it with:

$listener->add(array($this, 'bar'));

Answer 2

I don't think you can specify a callable this way...

Try

$listener->add(array($this, 'bar'));

And see http://php.net/manual/en/language.types.callable.php too.

Answer 3

Methods and properties have separate namespaces in PHP, which is why $this->bar evaluates to null: You're accessing an undefined property.

The correct way to create an array in the form of array($object, "methodName"):

Passing the callback correctly:

$listener->add(array($this, 'bar'));  

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The type hint you have given is okay—as of PHP 5.4, that is.