Get all dates in date range in SQL Server

Question

I got this example from one StackOverflow question that was asked but I couldn\'t get it work according to my need.

WITH DateTable
AS
(
    SELECT CAST(\'201         


        

Answer 1

create table Dates (Id int, FromDate date, ToDate date)
insert into Dates values (1, '2011-11-10', '2011-11-12')
insert into Dates values (2, '2011-12-12', '2011-12-14')

with DateTable as
(
    select FromDate as Dt, ToDate
    from Dates
    union all
    select DATEADD(D, 1, Dt), ToDate
    from DateTable
    where DATEADD(D, 1, Dt) <= ToDate
)
select ROW_NUMBER() over (order by Dt) as SN, Dt as Dates
from DateTable
order by Dt

Answer 2

With a little help of a numbers table.

declare @T table
(
  ID int identity primary key,
  FromDate date,
  ToDate date
)

insert into @T values
('2011-11-10', '2011-11-12'),
('2011-12-12', '2011-12-14')

select row_number() over(order by D.Dates) as SN,
       D.Dates
from @T as T
  inner join master..spt_values as N
    on N.number between 0 and datediff(day, T.FromDate, T.ToDate)
    cross apply (select dateadd(day, N.number, T.FromDate)) as D(Dates)
where N.type ='P'

Try on SE Data

Answer 3

What about this?

--DROP TABLE #Test
CREATE TABLE #Test(ID int, FromDate datetime, ToDate datetime)
INSERT INTO  #Test VALUES (1, '2011-11-10', '2011-11-12')
INSERT INTO  #Test VALUES (2, '2011-12-12', '2011-12-14')

;
WITH DateTable
AS
(
    SELECT  ID, FromDate, ToDate, 0 AS Seed FROM #Test
    UNION   ALL
    SELECT  ID, DATEADD(dd, 1, FromDate), ToDate, Seed + 1
    FROM    DateTable
    WHERE   DATEADD(dd, 1, FromDate) <= ToDate
)
SELECT  --*
        ROW_NUMBER() OVER (ORDER BY ID, Seed) SN, FromDate AS Dates
FROM    DateTable