Two arrays in foreach loop

Question

I want to generate a selectbox using two arrays, one containing the country codes and another containing the country names.

This is an example:

Answer 1

Walk it out...

$codes = array('tn','us','fr');
$names = array('Tunisia','United States','France');

• PHP 5.3+

  array_walk($codes, function ($code,$key) use ($names) { 
      echo '<option value="' . $code . '">' . $names[$key] . '</option>';
  });
  

• Before PHP 5.3

  array_walk($codes, function ($code,$key,$names){ 
      echo '<option value="' . $code . '">' . $names[$key] . '</option>';
  },$names);
  

• or combine

  array_walk(array_combine($codes,$names), function ($name,$code){ 
      echo '<option value="' . $code . '">' . $name . '</option>';
  })
  

• in select

  array_walk(array_combine($codes,$names), function ($name,$code){ 
      @$opts = '<option value="' . $code . '">' . $name . '</option>';
  })
  echo "<select>$opts</select>";
  

demo

Answer 2

Use array_combine() to fuse the arrays together and iterate over the result.

$countries = array_combine($codes, $names);

Answer 3

<?php

$codes = array ('tn','us','fr');
$names = array ('Tunisia','United States','France');

echo '<table>';

foreach(array_keys($codes) as $i) {

     echo '<tr><td>';
     echo ($i + 1);
     echo '</td><td>';
     echo $codes[$i];
     echo '</td><td>';
     echo $names[$i];
     echo '</td></tr>';
}

echo '</table>';

?>

Answer 4

it works for me

$counter = 0;
foreach($codes as $code)
{
$codes_array[$counter]=$code;
$counter++;
}
$counter = 0;
foreach($names as $name)
{
echo $codes_array[$counter]."and".$name;
$counter++;
}

Answer 5

All fully tested

3 ways to create a dynamic dropdown from an array.

This will create a dropdown menu from an array and automatically assign its respective value.

Method #1 (Normal Array)

<?php

$names = array('tn'=>'Tunisia','us'=>'United States','fr'=>'France');

echo '<select name="countries">';

foreach($names AS $let=>$word){
    echo '<option value="'.$let.'">'.$word.'</option>';
}
echo '</select>';
 
?>

---

---

Method #2 (Normal Array)

<select name="countries">

<?php

$countries = array('tn'=> "Tunisia", "us"=>'United States',"fr"=>'France');
foreach($countries as $select=>$country_name){
echo '<option value="' . $select . '">' . $country_name . '</option>';
}
?>

</select>

---

---

Method #3 (Associative Array)

<?php

$my_array = array(
     'tn' => 'Tunisia',
     'us' => 'United States',
     'fr' => 'France'
);

echo '<select name="countries">';
echo '<option value="none">Select...</option>';
foreach ($my_array as $k => $v) {
    echo '<option value="' . $k . '">' . $v . '</option>';
}
echo '</select>';
?>

Answer 6

I solved a problem like yours by this way:

foreach(array_keys($idarr) as $i) {
 echo "Student ID: ".$idarr[$i]."<br />";
 echo "Present: ".$presentarr[$i]."<br />";
 echo "Reason: ".$reasonarr[$i]."<br />";
 echo "Mark: ".$markarr[$i]."<br />";
}