Template base constructor call in member initialization list error

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执笔经年
执笔经年 2020-12-03 11:57

I have a base class that looks like the following:

template
class Base
{
   public:
      Base(int someValue);

      virtual T someFunc() =         


        
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  • 2020-12-03 12:25

    First:

    [C++11: 12.6.2/3]: A mem-initializer-list can initialize a base class using any class-or-decltype that denotes that base class type.

    [ Example:

    struct A { A(); };
    typedef A global_A;
    struct B { };
    struct C: public A, public B { C(); };
    C::C(): global_A() { } // mem-initializer for base A
    

    —end example ]

    And Base should be a valid injected-class-name for the base here (that is, you can use it in place of Base<T>):

    [C++11: 14.6.1/1]: Like normal (non-template) classes, class templates have an injected-class-name (Clause 9). The injected-class-name can be used as a template-name or a type-name. When it is used with a template-argument-list, as a template-argument for a template template-parameter, or as the final identifier in the elaborated-type-specifier of a friend class template declaration, it refers to the class template itself. Otherwise, it is equivalent to the template-name followed by the template-parameters of the class template enclosed in <>.

    [C++11: 14.6.1/3]: The injected-class-name of a class template or class template specialization can be used either as a template-name or a type-name wherever it is in scope. [ Example:

    template <class T> struct Base {
       Base* p;
    };
    
    template <class T> struct Derived: public Base<T> {
       typename Derived::Base* p; // meaning Derived::Base<T>
    };
    
    template<class T, template<class> class U = T::template Base> struct Third { };
    Third<Base<int> > t; // OK: default argument uses injected-class-name as a template
    

    —end example ]

    I haven't found anything to indicate that this doesn't apply in the ctor-initializer, so I'd say that this is a compiler bug.

    My stripped-down testcase fails in GCC 4.1.2 and GCC 4.3.4 but succeeds in GCC 4.5.1 (C++11 mode). It seems to be resolved by GCC bug 189; in the GCC 4.5 release notes:

    G++ now implements DR 176. Previously G++ did not support using the injected-class-name of a template base class as a type name, and lookup of the name found the declaration of the template in the enclosing scope. Now lookup of the name finds the injected-class-name, which can be used either as a type or as a template, depending on whether or not the name is followed by a template argument list. As a result of this change, some code that was previously accepted may be ill-formed because

    • The injected-class-name is not accessible because it's from a private base, or
    • The injected-class-name cannot be used as an argument for a template template parameter.

    In either of these cases, the code can be fixed by adding a nested-name-specifier to explicitly name the template. The first can be worked around with -fno-access-control; the second is only rejected with -pedantic.


    My stripped-down testcase with Qt abstracted out:

    template <typename T>
    struct Base { };
    
    struct Derived : Base<Derived> { // I love the smell of CRTP in the morning
       Derived();
    };
    
    Derived::Derived() : Base() {};
    
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