Printing using list comprehension

Question

From my Python console

>>> numbers = [1,2,3]
>>> [print(x) for x in numbers]
1
2
3
[None, None, None]

Why does this print

Answer 1

If this behaviour of the Print function bothers, I suggest you don't use the Print function in the list comprehension, just use the following one-liner which is compact and more Pythonic:

>>> [x for x in [1,2,3]]
[1, 2, 3]

Answer 2

A list comprehension is not the right tool for the job at hand. It'll always return a list, and given that print() evaluates to None, the list is filled with None values. A simple for loop works better when we're not interested in creating a list of values, only in evaluating a function with no returned value:

for x in numbers:
    print(x)

Answer 3

print is a function, it's just like

>>>def f(x):
...:   pass
>>>[f(x) for x in numbers]

Answer 4

An ugly way of doing this is _=[print(i) for i in somelist] It does work but is not encouraged:)

Answer 5

You can use the String Join() method and print the string. For example:

>>> print('\n'.join(numbers))
1
2
3
>>> print(', '.join(numbers))
1, 2, 3
>>> print(',\n'.join(numbers))
1,
2,
3

Answer 6

List comprehensions always return a list.

Based on this information, your print() statement must wrap the whole list comprehension argument:

Numbers = [1, 2, 3]

print([x for x in Numbers])

If you want to print items of a list one by one, a for loop is more suitable for this matter.