mySQL SELECT upcoming birthdays

Question

I\'m trying to write a query to select users of a database whose birthdays are in the next 7 days.

I\'ve done a lot of research but I can\'t come up with a working s

Answer 1

try this:

 Select * From persons
 where (DayOfYear(birthday) >= 7 
         And DayOfYear(birthday) - DayOfYear(curdate()) Between 0 and 6) Or
       (MOD(YEAR(curDate()),4) = 0) And MOD(YEAR(curDate()),100) != 0
        And (DayOfYear(birthday) + 366 - DayOfYear(curdate())) % 366 < 7) Or
         (DayOfYear(birthday) + 365 - DayOfYear(curdate())) % 365 < 7)

Answer 2

Here is a simple PHP Code & SQL Query to retrieve upcoming birthdays. Where date of birth is stored as DATE (YYYY-MM-DD Format). enter image description here

<?php
$conn = mysqli_connect('localhost', 'user', 'paasword', 'databasename');
$nod = 5;     //Number of days upto which you want to retrieve birthdays
$delim = $filter = "";
for($i=0;$i<$nod;$i++){
    $date = date_create(date('Y-m-d'));
    date_add($date,date_interval_create_from_date_string("$i days"));
    $filter .= $delim."'".date_format($date,"m-d")."'";
    $delim = ", ";
}
$sql = "SELECT NAME, DOB, MOBILE, EMAIL, TITLE FROM tablename WHERE SUBSTR(DOB,6) IN ($filter) ORDER BY SUBSTR(DOB,6) ASC";
$result = mysqli_query($conn, $sql);    
$i=0;
echo '
<table class="table-1 mt-2 table-responsive table-bordered">
    <tr>
        <th>S. No.</th>
        <th>Name</th>
        <th>DOB</th>
        <th>MOBILE</th>
    </tr>';
while($row = mysqli_fetch_array($result)){
    $i++;
    $dob = date('Y-').date_format(date_create($row["DOB"]),'m-d');
    $day = date_format(date_create($dob),'w');
    switch ($day){
        case 0:
            $day = "Sunday"; break;
        case 1:
            $day = "Monday"; break;
        case 2:
            $day = "Tuesday"; break;
        case 3:
            $day = "Wednesday"; break;
        case 4:
            $day = "Thursday"; break;
        case 5:
            $day = "Friday"; break;
        case 6:
            $day = "Saturday"; break;
    }
    echo"
    <tr>
        <td>".$i."</td>
        <td>".$row["NAME"]."</td>
        <td>".date_format(date_create($row["DOB"]),'d-m-Y')." $day</td>
        <td>".$row["MOBILE"]."</td>
    </tr>
    ";
}
echo"
</table>";
?>

Answer 3

I did a lot "researches" and here is my solution, I guess it is very easy to understand!

SELECT *,
(366 + DAYOFYEAR(birth_date) - DAYOFYEAR(NOW())) % 366 as left_days
FROM `profile`
ORDER BY left_days;

Answer 4

SELECT * from persons as p
WHERE   
MOD( DAYOFYEAR(p.bday) - DAYOFYEAR(CURRENT_DATE()) + 366, 366)  
BETWEEN 0 and 7  
ORDER by DAYOFYEAR(p.bday) ASC

This works for me.

Answer 5

I managed to get it working with this query. Due mostly to the help of Lobo's answer.

SELECT * 
FROM  persons 
WHERE  DATE_ADD(STR_TO_DATE(birthday, '%m/%d/%Y'), INTERVAL YEAR(CURDATE())-YEAR(STR_TO_DATE(birthday, '%m/%d/%Y')) YEAR) 
            BETWEEN CURDATE() AND DATE_ADD(CURDATE(), INTERVAL 7 DAY);

Answer 6

Any solution using DAYOFYEAR() will be flawed when the date of birth occurred during a leap year. Consider using TIMESTAMPDIFF() when working with age or birthdays.

Current age can be calculated as

timestampdiff(YEAR, person.date_of_birth, curdate())

Calculate the upcoming birthday by adding the age to their date of birth.

DATE_ADD(
    person.date_of_birth, 
    INTERVAL timestampdiff(YEAR, person.date_of_birth, curdate())+1 YEAR
)

Putting this together to solve the OP’s query

select
    DATE_ADD(
        person.date_of_birth, 
        INTERVAL timestampdiff(YEAR, date_add(person.date_of_birth,INTERVAL 1 DAY), curdate())+1 YEAR
    ) upcoming_birthday
from person
having upcoming_birthday between curdate() and DATE_ADD(curdate(), INTERVAL 7 DAY)

Notice that I have added one day to date_of_birth when calculating age, otherwise today’s birthdays would not be returned.