I can create an array and initialize it like this:
int a[] = {10, 20, 30};
How do I create a std::vector
and initialize it sim
If your compiler supports C++11, you can simply do:
std::vector<int> v = {1, 2, 3, 4};
This is available in GCC as of version 4.4. Unfortunately, VC++ 2010 seems to be lagging behind in this respect.
Alternatively, the Boost.Assign library uses non-macro magic to allow the following:
#include <boost/assign/list_of.hpp>
...
std::vector<int> v = boost::assign::list_of(1)(2)(3)(4);
Or:
#include <boost/assign/std/vector.hpp>
using namespace boost::assign;
...
std::vector<int> v;
v += 1, 2, 3, 4;
But keep in mind that this has some overhead (basically, list_of
constructs a std::deque
under the hood) so for performance-critical code you'd be better off doing as Yacoby says.
If your compiler supports Variadic macros (which is true for most modern compilers), then you can use the following macro to turn vector initialization into a one-liner:
#define INIT_VECTOR(type, name, ...) \
static const type name##_a[] = __VA_ARGS__; \
vector<type> name(name##_a, name##_a + sizeof(name##_a) / sizeof(*name##_a))
With this macro, you can define an initialized vector with code like this:
INIT_VECTOR(int, my_vector, {1, 2, 3, 4});
This would create a new vector of ints named my_vector with the elements 1, 2, 3, 4.
There are various ways to hardcode a vector, i will share few ways:
// Create an empty vector
vector<int> vect;
vect.push_back(10);
vect.push_back(20);
vect.push_back(30);
vector<int> vect{ 10, 20, 30 };
int arr[] = { 10, 20, 30 };
int n = sizeof(arr) / sizeof(arr[0]);
vector<int> vect(arr, arr + n);
vector<int> vect1{ 10, 20, 30 };
vector<int> vect2(vect1.begin(), vect1.end());
// Before C++11
// I used following methods:
// 1.
int A[] = {10, 20, 30}; // original array A
unsigned sizeOfA = sizeof(A)/sizeof(A[0]); // calculate the number of elements
// declare vector vArrayA,
std::vector<int> vArrayA(sizeOfA); // make room for all
// array A integers
// and initialize them to 0
for(unsigned i=0; i<sizeOfA; i++)
vArrayA[i] = A[i]; // initialize vector vArrayA
//2.
int B[] = {40, 50, 60, 70}; // original array B
std::vector<int> vArrayB; // declare vector vArrayB
for (unsigned i=0; i<sizeof(B)/sizeof(B[0]); i++)
vArrayB.push_back(B[i]); // initialize vArrayB
//3.
int C[] = {1, 2, 3, 4}; // original array C
std::vector<int> vArrayC; // create an empty vector vArrayC
vArrayC.resize(sizeof(C)/sizeof(C[0])); // enlarging the number of
// contained elements
for (unsigned i=0; i<sizeof(C)/sizeof(C[0]); i++)
vArrayC.at(i) = C[i]; // initialize vArrayC
// A Note:
// Above methods will work well for complex arrays
// with structures as its elements.
"How do I create an STL vector and initialize it like the above? What is the best way to do so with the minimum typing effort?"
The easiest way to initialize a vector as you've initialized your built-in array is using an initializer list which was introduced in C++11.
// Initializing a vector that holds 2 elements of type int.
Initializing:
std::vector<int> ivec = {10, 20};
// The push_back function is more of a form of assignment with the exception of course
//that it doesn't obliterate the value of the object it's being called on.
Assigning
ivec.push_back(30);
ivec
is 3 elements in size after Assigning (labeled statement) is executed.