How to get the children of the $(this) selector?

Question

I have a layout similar to this:

and would like to use a jQuery selector to selec

Answer 1

You could also use

$(this).find('img');

which would return all imgs that are descendants of the div

Answer 2

$(document).ready(function() {
  // When you click the DIV, you take it with "this"
  $('#my_div').click(function() {
    console.info('Initializing the tests..');
    console.log('Method #1: '+$(this).children('img'));
    console.log('Method #2: '+$(this).find('img'));
    // Here, i'm selecting the first ocorrence of <IMG>
    console.log('Method #3: '+$(this).find('img:eq(0)'));
  });
});

.the_div{
  background-color: yellow;
  width: 100%;
  height: 200px;
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div id="my_div" class="the_div">
  <img src="...">
</div>

Answer 3

If you need to get the first img that's down exactly one level, you can do

$(this).children("img:first")

Answer 4

The jQuery constructor accepts a 2nd parameter called context which can be used to override the context of the selection.

jQuery("img", this);

Which is the same as using .find() like this:

jQuery(this).find("img");

If the imgs you desire are only direct descendants of the clicked element, you can also use .children():

jQuery(this).children("img");

Answer 5

If your DIV tag is immediately followed by the IMG tag, you can also use:

$(this).next();

Answer 6

You may have 0 to many <img> tags inside of your <div>.

To find an element, use a .find().

To keep your code safe, use a .each().

Using .find() and .each() together prevents null reference errors in the case of 0 <img> elements while also allowing for handling of multiple <img> elements.

// Set the click handler on your div
$("body").off("click", "#mydiv").on("click", "#mydiv", function() {

  // Find the image using.find() and .each()
  $(this).find("img").each(function() {
  
        var img = this;  // "this" is, now, scoped to the image element
        
        // Do something with the image
        $(this).animate({
          width: ($(this).width() > 100 ? 100 : $(this).width() + 100) + "px"
        }, 500);
        
  });
  
});

#mydiv {
  text-align: center;
  vertical-align: middle;
  background-color: #000000;
  cursor: pointer;
  padding: 50px;
  
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>

<div id="mydiv">
  <img src="" width="100" height="100"/>
</div>