How can I split this comma-delimited string in Python? [duplicate]

Answer 1

You don't want regular expressions here.

s = "144,1231693144,26959535291011309493156476344723991336010898738574164086137773096960,26959535291011309493156476344723991336010898738574164086137773096960,1.00,4295032833,1563,2747941 288,1231823695,26959535291011309493156476344723991336010898738574164086137773096960,26959535291011309493156476344723991336010898738574164086137773096960,1.00,4295032833,909,4725008"

print s.split(',')

Gives you:

['144', '1231693144', '26959535291011309493156476344723991336010898738574164086137773096960', '26959535291011309493156476344723991336010898738574164086137773096960', '1.00
', '4295032833', '1563', '2747941 288', '1231823695', '26959535291011309493156476344723991336010898738574164086137773096960', '26959535291011309493156476344723991336010898
738574164086137773096960', '1.00', '4295032833', '909', '4725008']

Answer 2

How about a list?

mystring.split(",")

It might help if you could explain what kind of info we are looking at. Maybe some background info also?

EDIT:

I had a thought you might want the info in groups of two?

then try:

re.split(r"\d*,\d*", mystring)

and also if you want them into tuples

[(pair[0], pair[1]) for match in re.split(r"\d*,\d*", mystring) for pair in match.split(",")]

in a more readable form:

mylist = []
for match in re.split(r"\d*,\d*", mystring):
    for pair in match.split(",")
        mylist.append((pair[0], pair[1]))

Answer 3

Question is a little vague.

list_of_lines = multiple_lines.split("\n")
for line in list_of_lines:
    list_of_items_in_line = line.split(",")
    first_int = int(list_of_items_in_line[0])

etc.