Sort an array in Java

Question

I\'m trying to make a program that consists of an array of 10 integers which all has a random value, so far so good.

However, now I need to sort them in order from l

Answer 1

Take a look at Arrays.sort()

Answer 2

You may use Arrays.sort() function.

sort() method is a java.util.Arrays class method.          
Declaration : Arrays.sort(arrName)

Answer 3

Add the Line before println and your array gets sorted

Arrays.sort( array );

Answer 4

See below, it will give you sorted ascending and descending both

import java.util.Arrays;
import java.util.Collections;

public class SortTestArray {

/**
 * Example method for sorting an Integer array
 * in reverse & normal order.
 */
public void sortIntArrayReverseOrder() {

    Integer[] arrayToSort = new Integer[] {
        new Integer(48),
        new Integer(5),
        new Integer(89),
        new Integer(80),
        new Integer(81),
        new Integer(23),
        new Integer(45),
        new Integer(16),
        new Integer(2)
    };

    System.out.print("General Order is    : ");

    for (Integer i : arrayToSort) {
        System.out.print(i.intValue() + " ");
    }


    Arrays.sort(arrayToSort);

    System.out.print("\n\nAscending Order is  : ");

    for (Integer i : arrayToSort) {
        System.out.print(i.intValue() + " ");
    }


    Arrays.sort(arrayToSort, Collections.reverseOrder());
    System.out.print("\n\nDescinding Order is : ");
    for (Integer i : arrayToSort) {
        System.out.print(i.intValue() + " ");
    }

}


/**
 * @param args the command line arguments
 */
public static void main(String[] args) {
    SortTestArray SortTestArray = new SortTestArray();
    SortTestArray.sortIntArrayReverseOrder();
}}

Output will be

General Order is    : 48 5 89 80 81 23 45 16 2 

Ascending Order is  : 2 5 16 23 45 48 80 81 89 

Descinding Order is : 89 81 80 48 45 23 16 5 2 

Note: You can use Math.ranodm instead of adding manual numbers. Let me know if I need to change the code...

Good Luck... Cheers!!!

Answer 5

I was lazy and added the loops

import java.util.Arrays;


public class Sort {
    public static void main(String args[])
    {
        int [] array = new int[10];
        for ( int i = 0 ; i < array.length ; i++ ) {
            array[i] = ((int)(Math.random()*100+1));
        }
        Arrays.sort( array );
        for ( int i = 0 ; i < array.length ; i++ ) {
            System.out.println(array[i]);
        }
    }
}

Your array has a length of 10. You need one variable (i) which takes the values from 0to 9.

for ( int i = 0  ; i < array.length ;   i++ ) 
       ^               ^                   ^
       |               |                   ------  increment ( i = i + 1 )
       |               |
       |               +-------------------------- repeat as long i < 10
       +------------------------------------------ start value of i


Arrays.sort( array );

Is a library methods that sorts arrays.