How to display two table columns per row in php loop

Answer 1

<table>
<?php
   $i=0;
   foreach ($x as $key=>$value)
   {
      if (!$i%2) echo '<tr>';
      echo '<td>',$value,'</td>';
      if ($i%2) echo '</tr>';
      $i++;
   }
?>
</table>

Answer 2

$i=0;
foreach ($x as $key=>$value)
  {
  if (fmod($i,2)) echo '<tr>';
  echo '<td>',$value,'</td>';
  if (fmod($i,2)) echo '</tr>';
  $i++;
  }

this will output TR (row) each second time

ps: i haven't tested the code, so maybe you will need to add ! sign before fmod, if it doesn't output TR on first iteration, but on second iteration in the beginning...

Answer 3

This would give you great table and for loop concept--

<table border="1" cellspacing="0" cellpadding="2">

<?php

     for($x=1; $x<=20; $x++)
        {
         echo "<tr>";
        for($y=1; $y<=20; $y++)
           {
          echo "<td>";
          echo $x*$y;
          echo "</td>"; 
           }
         echo "</tr>";
        }
?>
</table>

Answer 4

You can use array_chunk() to split an array of data into smaller arrays, in this case of length 2, for each row.

<table>
<?php foreach (array_chunk($values, 2) as $row) { ?>
    <tr>
    <?php foreach ($row as $value) { ?>
        <td><?php echo htmlentities($value); ?></td>
    <?php } ?>
    </tr>
<?php } ?>
</table>

Note that if you have an odd number of values, this will leave a final row with only one cell. If you want to add an empty cell if necessary, you could check the length of $row within the outer foreach.