I want to check if a string is in a text file. If it is, do X. If it\'s not, do Y. However, this code always returns True
for some reason. Can anyone see what i
Your check
function should return the found
boolean and use that to determine what to print.
def check():
datafile = file('example.txt')
found = False
for line in datafile:
if blabla in line:
found = True
break
return found
found = check()
if found:
print "true"
else:
print "false"
the second block could also be condensed to:
if check():
print "true"
else:
print "false"
If user wants to search for the word in given text file.
fopen = open('logfile.txt',mode='r+')
fread = fopen.readlines()
x = input("Enter the search string: ")
for line in fread:
if x in line:
print(line)
I made a little function for this purpose. It searches for a word in the input file and then adds it to the output file.
def searcher(outf, inf, string):
with open(outf, 'a') as f1:
if string in open(inf).read():
f1.write(string)
if True:
print "true"
This always happens because True is always True.
You want something like this:
if check():
print "true"
else:
print "false"
Good luck!
As Jeffrey Said, you are not checking the value of check()
. In addition, your check()
function is not returning anything. Note the difference:
def check():
with open('example.txt') as f:
datafile = f.readlines()
found = False # This isn't really necessary
for line in datafile:
if blabla in line:
# found = True # Not necessary
return True
return False # Because you finished the search without finding
Then you can test the output of check()
:
if check():
print('True')
else:
print('False')
found = False
def check():
datafile = file('example.txt')
for line in datafile:
if "blabla" in line:
found = True
break
return found
if check():
print "found"
else:
print "not found"