What are the differences between concatenating strings with cat
and paste
?
In particular, I have the following questions.
cat
and paste
are to be used in very different situations.
paste
is not print
When you paste
something and don't assign it to anything, it becomes a character
variable that is print
-ed using print.default
, the default method for character
, hence the quotes, etc. You can look at the help for print.default
for understanding how to modify what the output looks like.
print.default
will not evaluate escape characters such as \n
within a character string.Look at the answers to this question for how to capture the output from cat
.
Quoting from the easy to read help for cat
(?cat
)
Concatenate and Print
Description
Outputs the objects, concatenating the representations.
cat
performs much less conversion than...
Details
cat
is useful for producing output in user-defined functions. It converts its arguments tocharacter
vectors, concatenates them to a singlecharacter
vector, appends the givensep= string(s)
to each element and then outputs them.Value
None (invisible
NULL
).
cat
will not return anything, it will just output to the console or another connection.
Thus, if you try to run length(cat('x'))
or mode(cat('x'))
, you are running mode(NULL)
or length(NULL)
, which will return NULL
.
The help for paste is equally helpful and descriptive
Concatenate Strings
Description
Concatenate vectors after converting to
character
.....
Value
A
character
vector of the concatenated values. This will be of length zero if all the objects are, unless collapse is non-NULL
in which case it is a single empty string.