Convert a list to a dictionary in Python

Question

Let\'s say I have a list a in Python whose entries conveniently map to a dictionary. Each even element represents the key to the dictionary, and the following o

Answer 1

You can do it pretty fast without creating extra arrays, so this will work even for very large arrays:

dict(izip(*([iter(a)]*2)))

If you have a generator a, even better:

dict(izip(*([a]*2)))

Here's the rundown:

iter(h)    #create an iterator from the array, no copies here
[]*2       #creates an array with two copies of the same iterator, the trick
izip(*())  #consumes the two iterators creating a tuple
dict()     #puts the tuples into key,value of the dictionary

Answer 2

Simple answer

Another option (courtesy of Alex Martelli - source):

dict(x[i:i+2] for i in range(0, len(x), 2))

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Related note

If you have this:

a = ['bi','double','duo','two']

and you want this (each element of the list keying a given value (2 in this case)):

{'bi':2,'double':2,'duo':2,'two':2}

you can use:

>>> dict((k,2) for k in a)
{'double': 2, 'bi': 2, 'two': 2, 'duo': 2}

Answer 3

try below code:

  >>> d2 = dict([('one',1), ('two', 2), ('three', 3)])
  >>> d2
      {'three': 3, 'two': 2, 'one': 1}

Answer 4

{x: a[a.index(x)+1] for x in a if a.index(x) % 2 ==0}

result : {'hello': 'world', '1': '2'}

Answer 5

I am also very much interested to have a one-liner for this conversion, as far such a list is the default initializer for hashed in Perl.

Exceptionally comprehensive answer is given in this thread -

• python convert list to dictionary

Mine one I am newbie in Python), using Python 2.7 Generator Expressions, would be:

dict((a[i], a[i + 1]) for i in range(0, len(a) - 1, 2))

Answer 6

b = dict(zip(a[::2], a[1::2]))

If a is large, you will probably want to do something like the following, which doesn't make any temporary lists like the above.

from itertools import izip
i = iter(a)
b = dict(izip(i, i))

In Python 3 you could also use a dict comprehension, but ironically I think the simplest way to do it will be with range() and len(), which would normally be a code smell.

b = {a[i]: a[i+1] for i in range(0, len(a), 2)}

So the iter()/izip() method is still probably the most Pythonic in Python 3, although as EOL notes in a comment, zip() is already lazy in Python 3 so you don't need izip().

i = iter(a)
b = dict(zip(i, i))

If you want it on one line, you'll have to cheat and use a semicolon. ;-)