Convert a list to a dictionary in Python

Question

Let\'s say I have a list a in Python whose entries conveniently map to a dictionary. Each even element represents the key to the dictionary, and the following o

Answer 1

You can also try this approach save the keys and values in different list and then use dict method

data=['test1', '1', 'test2', '2', 'test3', '3', 'test4', '4']

keys=[]
values=[]
for i,j in enumerate(data):
    if i%2==0:
        keys.append(j)
    else:
        values.append(j)

print(dict(zip(keys,values)))

output:

{'test3': '3', 'test1': '1', 'test2': '2', 'test4': '4'}

Answer 2

May not be the most pythonic, but

>>> b = {}
>>> for i in range(0, len(a), 2):
        b[a[i]] = a[i+1]

Answer 3

You can also do it like this (string to list conversion here, then conversion to a dictionary)

    string_list = """
    Hello World
    Goodbye Night
    Great Day
    Final Sunset
    """.split()

    string_list = dict(zip(string_list[::2],string_list[1::2]))

    print string_list

Answer 4

You can use a dict comprehension for this pretty easily:

a = ['hello','world','1','2']

my_dict = {item : a[index+1] for index, item in enumerate(a) if index % 2 == 0}

This is equivalent to the for loop below:

my_dict = {}
for index, item in enumerate(a):
    if index % 2 == 0:
        my_dict[item] = a[index+1]

Answer 5

I am not sure if this is pythonic, but seems to work

def alternate_list(a):
   return a[::2], a[1::2]

key_list,value_list = alternate_list(a)
b = dict(zip(key_list,value_list))

Answer 6

Something i find pretty cool, which is that if your list is only 2 items long:

ls = ['a', 'b']
dict([ls])
>>> {'a':'b'}

Remember, dict accepts any iterable containing an iterable where each item in the iterable must itself be an iterable with exactly two objects.