Replace multiple strings with multiple other strings

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 18  1997

I\'m trying to replace multiple words in a string with multiple other words. The string is \"I have a cat, a dog, and a goat.\"

However, this does not produce \"I ha

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醉酒成梦

2020-11-22 05:00

I expanded on @BenMcCormicks a bit. His worked for regular strings but not if I had escaped characters or wildcards. Here's what I did

str = "[curl] 6: blah blah 234433 blah blah";
mapObj = {'\\[curl] *': '', '\\d: *': ''};


function replaceAll (str, mapObj) {

    var arr = Object.keys(mapObj),
        re;

    $.each(arr, function (key, value) {
        re = new RegExp(value, "g");
        str = str.replace(re, function (matched) {
            return mapObj[value];
        });
    });

    return str;

}
replaceAll(str, mapObj)

returns "blah blah 234433 blah blah"

This way it will match the key in the mapObj and not the matched word'

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攒了一身酷

2020-11-22 05:01

<!DOCTYPE html>
<html>
<body>



<p id="demo">Mr Blue 
has a           blue house and a blue car.</p>

<button onclick="myFunction()">Try it</button>

<script>
function myFunction() {
    var str = document.getElementById("demo").innerHTML;
    var res = str.replace(/\n| |car/gi, function myFunction(x){

if(x=='\n'){return x='<br>';}
if(x==' '){return x='&nbsp';}
if(x=='car'){return x='BMW'}
else{return x;}//must need



});

    document.getElementById("demo").innerHTML = res;
}
</script>

</body>
</html>

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甜味超标

2020-11-22 05:03
Specific Solution

You can use a function to replace each one.
```
var str = "I have a cat, a dog, and a goat.";
var mapObj = {
   cat:"dog",
   dog:"goat",
   goat:"cat"
};
str = str.replace(/cat|dog|goat/gi, function(matched){
  return mapObj[matched];
});
```
jsfiddle example

Generalizing it

If you want to dynamically maintain the regex and just add future exchanges to the map, you can do this
```
new RegExp(Object.keys(mapObj).join("|"),"gi"); 
```
to generate the regex. So then it would look like this
```
var mapObj = {cat:"dog",dog:"goat",goat:"cat"};

var re = new RegExp(Object.keys(mapObj).join("|"),"gi");
str = str.replace(re, function(matched){
  return mapObj[matched];
});
```
And to add or change any more replacements you could just edit the map.

fiddle with dynamic regex

Making it Reusable

If you want this to be a general pattern you could pull this out to a function like this
```
function replaceAll(str,mapObj){
    var re = new RegExp(Object.keys(mapObj).join("|"),"gi");

    return str.replace(re, function(matched){
        return mapObj[matched.toLowerCase()];
    });
}
```
So then you could just pass the str and a map of the replacements you want to the function and it would return the transformed string.

fiddle with function

To ensure Object.keys works in older browsers, add a polyfill eg from MDN or Es5.
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灰色年华

2020-11-22 05:07
Use numbered items to prevent replacing again. eg
```
let str = "I have a %1, a %2, and a %3";
let pets = ["dog","cat", "goat"];
```
then
```
str.replace(/%(\d+)/g, (_, n) => pets[+n-1])
```
How it works:- %\d+ finds the numbers which come after a %. The brackets capture the number.

This number (as a string) is the 2nd parameter, n, to the lambda function.

The +n-1 converts the string to the number then 1 is subtracted to index the pets array.

The %number is then replaced with the string at the array index.

The /g causes the lambda function to be called repeatedly with each number which is then replaced with a string from the array.

In modern JavaScript:-
```
replace_n=(str,...ns)=>str.replace(/%(\d+)/g,(_,n)=>ns[n-1])
```
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闹比i

2020-11-22 05:07

This worked for me:

String.prototype.replaceAll = function(search, replacement) {
    var target = this;
    return target.replace(new RegExp(search, 'g'), replacement);
};

function replaceAll(str, map){
    for(key in map){
        str = str.replaceAll(key, map[key]);
    }
    return str;
}

//testing...
var str = "bat, ball, cat";
var map = {
    'bat' : 'foo',
    'ball' : 'boo',
    'cat' : 'bar'
};
var new = replaceAll(str, map);
//result: "foo, boo, bar"

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余生分开走

2020-11-22 05:07

With my replace-once package, you could do the following:

const replaceOnce = require('replace-once')

var str = 'I have a cat, a dog, and a goat.'
var find = ['cat', 'dog', 'goat']
var replace = ['dog', 'goat', 'cat']
replaceOnce(str, find, replace, 'gi')
//=> 'I have a dog, a goat, and a cat.'

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Replace multiple strings with multiple other strings

Specific Solution

Generalizing it

Making it Reusable