how to find the owner of a file or directory in python

Question

I need a function or method in Python to find the owner of a file or directory.

The function should be like:

>>> find_owner(\"/home/somedir         


        

Answer 1

On Windows this Works but uses the cli

import os
from subprocess import Popen, PIPE
from collections import namedtuple


def sliceit(iterable, tup):
    return iterable[tup[0]:tup[1]].strip()

def convert_cat(line):
    # Column Align Text indicies from cmd
    # Date time dir filesize owner filename
    Stat = namedtuple('Stat', 'date time directory size owner filename')
    stat_index = Stat(date=(0, 11), 
                      time=(11, 18), 
                      directory=(18, 27), 
                      size=(27, 35), 
                      owner=(35, 59), 
                      filename=(59, -1))

    stat = Stat(date=sliceit(line, stat_index.date),
                      time=sliceit(line, stat_index.time),
                      directory=sliceit(line, stat_index.directory),
                      size=sliceit(line, stat_index.size),
                      owner=sliceit(line, stat_index.owner),
                      filename=sliceit(line, stat_index.filename))
    return stat

def stat(path):
    if not os.path.isdir(path):
        dirname, filename = os.path.split(path)
    else:
        dirname = path
    cmd = ["cmd", "/c", "dir", dirname, "/q"]
    session = Popen(cmd, stdin=PIPE, stdout=PIPE, stderr=PIPE)
    # cp1252 is common on my Norwegian Computer,
    # check encoding from your windows system
    result = session.communicate()[0].decode('cp1252')

    if os.path.isdir(path):
        line = result.splitlines()[5]
        return convert_cat(line)
    else:
        for line in result.splitlines()[5:]:
            if filename in line:
                return convert_cat(line)
        else:
            raise Exception('Could not locate file')

if __name__ == '__main__':
    print(stat('C:\\temp').owner)
    print(stat('C:\\temp\\diff.py'))