generating variable names on fly in python [duplicate]

Answer 1

Another example, which is really a variation of another answer, in that it uses a dictionary too:

>>> vr={} 
... for num in range(1,4): 
...     vr[str(num)] = 5 + num
...     
>>> print vr["3"]
8
>>> 

Answer 2

On an object, you can achieve this with setattr

>>> class A(object): pass
>>> a=A()
>>> setattr(a, "hello1", 5)
>>> a.hello1
5

Answer 3

bit long, it works i guess...

prices = [5, 12, 45]
names = []
for i, _ in enumerate(prices):
    names.append("price"+str(i+1))
dict = {}
for name, price in zip(names, prices):
    dict[name] = price
for item in dict:
    print(item, "=", dict[item])

Answer 4

Though I don't see much point, here it is:

for i in xrange(0, len(prices)):
    exec("price%d = %s" % (i + 1, repr(prices[i])));

Answer 5

If you really want to create them on the fly you can assign to the dict that is returned by either globals() or locals() depending on what namespace you want to create them in:

globals()['somevar'] = 'someval'
print somevar  # prints 'someval'

But I wouldn't recommend doing that. In general, avoid global variables. Using locals() often just obscures what you are really doing. Instead, create your own dict and assign to it.

mydict = {}
mydict['somevar'] = 'someval'
print mydict['somevar']

Learn the python zen; run this and grok it well:

>>> import this

Answer 6

I got your problem , and here is my answer:

prices = [5, 12, 45]
list=['1','2','3']

for i in range(1,3):
  vars()["prices"+list[0]]=prices[0]
print ("prices[i]=" +prices[i])

so while printing:

price1 = 5 
price2 = 12
price3 = 45