how does tensorflow indexing work

Question

I\'m having trouble understanding a basic concept with tensorflow. How does indexing work for tensor read/write operations? In order to make this specific, how can the follo

Answer 1

There's github issue #206 to support this nicely, meanwhile you have to resort to verbose work-arounds

The first example can be done with tf.select that combines two same-shaped tensors by selecting each element from one or the other

tf.reset_default_graph()
row_indices = tf.constant([1, 1, 2])
col_indices = tf.constant([0, 2, 3])
x = tf.zeros((3, 4))
sess = tf.InteractiveSession()

# get list of ((row1, col1), (row2, col2), ..)
coords = tf.transpose(tf.pack([row_indices, col_indices]))

# get tensor with 1's at positions (row1, col1),...
binary_mask = tf.sparse_to_dense(coords, x.get_shape(), 1)

# convert 1/0 to True/False
binary_mask = tf.cast(binary_mask, tf.bool)

twos = 2*tf.ones(x.get_shape())

# make new x out of old values or 2, depending on mask 
x = tf.select(binary_mask, twos, x)

print x.eval()

gives

[[ 0.  0.  0.  0.]
 [ 2.  0.  2.  0.]
 [ 0.  0.  0.  2.]]

The second one could be done with scatter_update, except scatter_update only supports on linear indices and works on variables. So you could create a temporary variable and use reshaping like this. (to avoid variables you could use dynamic_stitch, see the end)

# get linear indices
linear_indices = row_indices*x.get_shape()[1]+col_indices

# turn 'x' into 1d variable since "scatter_update" supports linear indexing only
x_flat = tf.Variable(tf.reshape(x, [-1]))

# no automatic promotion, so make updates float32 to match x
updates = tf.constant([5, 4, 3], dtype=tf.float32)

sess.run(tf.initialize_all_variables())
sess.run(tf.scatter_update(x_flat, linear_indices,  updates))

# convert back into original shape
x = tf.reshape(x_flat, x.get_shape())

print x.eval()

gives

[[ 0.  0.  0.  0.]
 [ 5.  0.  4.  0.]
 [ 0.  0.  0.  3.]]

Finally the third example is already supported with gather_nd, you write

print tf.gather_nd(x, coords).eval()

To get

[ 5.  4.  3.]

Edit, May 6

The update x[cols,rows]=newvals can be done without using Variables (which occupy memory between session run calls) by using select with sparse_to_dense that takes vector of sparse values, or relying on dynamic_stitch

sess = tf.InteractiveSession()
x = tf.zeros((3, 4))
row_indices = tf.constant([1, 1, 2])
col_indices = tf.constant([0, 2, 3])

# no automatic promotion, so specify float type
replacement_vals = tf.constant([5, 4, 3], dtype=tf.float32)

# convert to linear indexing in row-major form
linear_indices = row_indices*x.get_shape()[1]+col_indices
x_flat = tf.reshape(x, [-1])

# use dynamic stitch, it merges the array by taking value either
# from array1[index1] or array2[index2], if indices conflict,
# the later one is used 
unchanged_indices = tf.range(tf.size(x_flat))
changed_indices = linear_indices
x_flat = tf.dynamic_stitch([unchanged_indices, changed_indices],
                           [x_flat, replacement_vals])
x = tf.reshape(x_flat, x.get_shape())
print x.eval()