MySQL: Count the distinct rows per day

Question

I have an interesting query I need to do. I have a table with an INT column containing ip address numbers (using INET_ATON), and a timestamp<

Answer 1

Here's how you'd get counts per day for the last 7 days:

select
    count(*) as count,
    date(timestamp) as date
from
    tablename
where
    timestamp >= date_sub(curdate(), interval 7 day)
group by 
    date;

+-------------+------------+
| count       | date       |
+-------------+------------+
| #forThatDay | 2020-02-21 |
| #forThatDay | 2020-02-22 |
| #forThatDay | 2020-02-22 |
| #forThatDay | 2020-02-23 |
| #forThatDay | 2020-02-24 |
| #forThatDay | 2020-02-25 |
| #forThatDay | 2020-02-26 |
+-------------+------------+
7 rows in set (0.03 sec)

group by the ipNum column first to get distinct counts of that column per day:

select
    count(*) as count,
    date(timestamp) as date
from
    tablename
where
    timestamp >= date_sub(curdate(), interval 7 day)
group by 
    ipNum, date;

Answer 2

$log_date     = date('Y-m-d H:i:s');
$log_date     = date('Y-m-d H:i:s', strtotime($log_date.' -1 hour'));
SELECT ipNum, COUNT(ipNum), COUNT(DISTINCT ipNum), DATE(timestamp), timestamp FROM tableName  WHERE `timestamp` > '".$log_date."' GROUP BY ipNum ORDER BY DATE(timestamp) DESC  

THIS WILL GIVE YOU A RESULT LIKE

 ip                  TIME               COUNTIPS
11.237.115.30     2018-01-27 19:13:51       1
21.744.133.52     2018-01-27 19:14:03       1
44.628.197.51     2018-01-27 19:48:12       14

Answer 3

SELECT  DATE(timestamp) Date, COUNT(DISTINCT ipNum) totalCOunt
FROM    tableName
GROUP   BY  DATE(timestamp)

• SQLFiddle Demo