How to SELECT by MAX(date)?

Question

This is the table structure:

CREATE TABLE `reports` (
  `report_id` int(11) NOT NULL auto_increment,
  `computer_id` int(11) NOT NULL default \'0\',
  `date_e         


        

Answer 1

I use this solution having max(date_entered) and it works very well

SELECT 
  report_id, 
  computer_id, 
  date_entered
FROM reports
GROUP BY computer_id having max(date_entered)

Answer 2

SELECT report_id, computer_id, date_entered
FROM reports
WHERE date_entered = (
    SELECT date_entered 
    FROM reports 
    ORDER date_entered 
    DESC LIMIT 1
)

Answer 3

select report_id, computer_id, date_entered
into #latest_date
from reports a
where exists(select 'x' from reports 
                where a.report_id = report_id
                group by report_id having max(date_entered) =   a.date_entered)

select * from #latest_leave where computer_id = ##

Answer 4

It works great for me

SELECT report_id,computer_id,MAX(date_entered) FROM reports GROUP BY computer_id

Answer 5

Are you only wanting it to show the last date_entered, or to order by starting with the last_date entered?

SELECT report_id, computer_id, date_entered
FROM reports
GROUP BY computer_id
ORDER BY date_entered DESC
-- LIMIT 1 -- uncomment to only show the last date.

Answer 6

Accordig to this: https://bugs.mysql.com/bug.php?id=54784 casting as char should do the trick:

SELECT report_id, computer_id, MAX(CAST(date_entered AS CHAR))
FROM reports
GROUP BY report_id, computer_id