Could not open ServletContext resource [/WEB-INF/applicationContext.xml]

Question

Ok, I am 500th user asking this question, I read many answers but still having no luck.

parent module pom contains:

Answer 1

Update: This will create a second context same as in applicationContext.xml

or you can add this code snippet to your web.xml

<servlet>
    <servlet-name>spring-dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
          <param-name>contextConfigLocation</param-name>
          <param-value>classpath:applicationContext.xml</param-value>
        </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>

instead of

<servlet>
    <servlet-name>dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <load-on-startup>1</load-on-startup>
</servlet>

Answer 2

ContextLoaderListener has its own context which is shared by all servlets and filters. By default it will search /WEB-INF/applicationContext.xml

You can customize this by using

<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>/WEB-INF/somewhere-else/root-context.xml</param-value>
</context-param>

on web.xml, or remove this listener if you don't need one.