How to do scanf for single char in C [duplicate]

Answer 1

The only code that worked for me is:

scanf(" %c",&c);

I was having the same problem, and only with single characters. After an hour of random testing I can not report an issue yet. One would think that C would have by now a bullet-proof function to retrieve single characters from the keyboard, and not an array of possible hackarounds... Just saying...

Answer 2

You have to use a valid variable. ch is not a valid variable for this program. Use char Aaa;

char aaa;
scanf("%c",&Aaa);

Tested and it works.

Answer 3

neither fgets nor getchar works to solve the problem. the only workaround is keeping a space before %c while using scanf scanf(" %c",ch); // will only work

In the follwing fgets also not work..

char line[256];
char ch;
int i;

printf("Enter a num : ");
scanf("%d",&i);
printf("Enter a char : ");

if (fgets(line, sizeof line, stdin) == NULL) {
    printf("Input error.\n");
    exit(1);
}

ch = line[0];
printf("Character read: %c\n", ch);

Answer 4

Before the scanf put fflush(stdin); to clear buffer.

Answer 5

This works for me try it out

int main(){
char c;
scanf(" %c",&c);
printf("%c",c);
return 0;
}

Answer 6

Here is a similiar thing that I would like to share,

while you're working on Visual Studio you could get an error like:

'scanf': function or variable may be unsafe. Consider using scanf_s instead. To disable deprecation, use _CRT_SECURE_NO_WARNINGS

To prevent this, you should write it in the following format

A single character may be read as follows:

char c;
scanf_s("%c", &c, 1);

When multiple characters for non-null terminated strings are read, integers are used as the width specification and the buffer size.

char c[4];
scanf_s("%4c", &c, _countof(c));