Response.Redirect with POST instead of Get?

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We have the requirement to take a form submission and save some data, then redirect the user to a page offsite, but in redirecting, we need to \"submit\" a form with POST, n

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渐次进展

2020-11-22 04:24

Copy-pasteable code based on Pavlo Neyman's method

RedirectPost(string url, T bodyPayload) and GetPostData() are for those who just want to dump some strongly typed data in the source page and fetch it back in the target one. The data must be serializeable by NewtonSoft Json.NET and you need to reference the library of course.

Just copy-paste into your page(s) or better yet base class for your pages and use it anywhere in you application.

My heart goes out to all of you who still have to use Web Forms in 2019 for whatever reason.

        protected void RedirectPost(string url, IEnumerable<KeyValuePair<string,string>> fields)
        {
            Response.Clear();

            const string template =
@"<html>
<body onload='document.forms[""form""].submit()'>
<form name='form' action='{0}' method='post'>
{1}
</form>
</body>
</html>";

            var fieldsSection = string.Join(
                    Environment.NewLine,
                    fields.Select(x => $"<input type='hidden' name='{HttpUtility.UrlEncode(x.Key)}' value='{HttpUtility.UrlEncode(x.Value)}'>")
                );

            var html = string.Format(template, HttpUtility.UrlEncode(url), fieldsSection);

            Response.Write(html);

            Response.End();
        }

        private const string JsonDataFieldName = "_jsonData";

        protected void RedirectPost<T>(string url, T bodyPayload)
        {
            var json = JsonConvert.SerializeObject(bodyPayload, Formatting.Indented);
            //explicit type declaration to prevent recursion
            IEnumerable<KeyValuePair<string, string>> postFields = new List<KeyValuePair<string, string>>()
                {new KeyValuePair<string, string>(JsonDataFieldName, json)};

            RedirectPost(url, postFields);

        }

        protected T GetPostData<T>() where T: class 
        {
            var urlEncodedFieldData = Request.Params[JsonDataFieldName];
            if (string.IsNullOrEmpty(urlEncodedFieldData))
            {
                return null;// default(T);
            }

            var fieldData = HttpUtility.UrlDecode(urlEncodedFieldData);

            var result = JsonConvert.DeserializeObject<T>(fieldData);
            return result;
        }

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灰色年华

2020-11-22 04:29

HttpWebRequest is used for this.

On postback, create a HttpWebRequest to your third party and post the form data, then once that is done, you can Response.Redirect wherever you want.

You get the added advantage that you don't have to name all of your server controls to make the 3rd parties form, you can do this translation when building the POST string.

string url = "3rd Party Url";

StringBuilder postData = new StringBuilder();

postData.Append("first_name=" + HttpUtility.UrlEncode(txtFirstName.Text) + "&");
postData.Append("last_name=" + HttpUtility.UrlEncode(txtLastName.Text));

//ETC for all Form Elements

// Now to Send Data.
StreamWriter writer = null;

HttpWebRequest request = (HttpWebRequest)WebRequest.Create(url);
request.Method = "POST";
request.ContentType = "application/x-www-form-urlencoded";                        
request.ContentLength = postData.ToString().Length;
try
{
    writer = new StreamWriter(request.GetRequestStream());
    writer.Write(postData.ToString());
}
finally
{
    if (writer != null)
        writer.Close();
}

Response.Redirect("NewPage");

However, if you need the user to see the response page from this form, your only option is to utilize Server.Transfer, and that may or may not work.

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一个人的身影

2020-11-22 04:33
Doing this requires understanding how HTTP redirects work. When you use Response.Redirect(), you send a response (to the browser that made the request) with HTTP Status Code 302, which tells the browser where to go next. By definition, the browser will make that via a GET request, even if the original request was a POST.

Another option is to use HTTP Status Code 307, which specifies that the browser should make the redirect request in the same way as the original request, but to prompt the user with a security warning. To do that, you would write something like this:
```
public void PageLoad(object sender, EventArgs e)
{
    // Process the post on your side   

    Response.Status = "307 Temporary Redirect";
    Response.AddHeader("Location", "http://example.com/page/to/post.to");
}
```
Unfortunately, this won't always work. Different browsers implement this differently, since it is not a common status code.

Alas, unlike the Opera and FireFox developers, the IE developers have never read the spec, and even the latest, most secure IE7 will redirect the POST request from domain A to domain B without any warnings or confirmation dialogs! Safari also acts in an interesting manner, while it does not raise a confirmation dialog and performs the redirect, it throws away the POST data, effectively changing 307 redirect into the more common 302.

So, as far as I know, the only way to implement something like this would be to use Javascript. There are two options I can think of off the top of my head:
1. Create the form and have its action attribute point to the third-party server. Then, add a click event to the submit button that first executes an AJAX request to your server with the data, and then allows the form to be submitted to the third-party server.
2. Create the form to post to your server. When the form is submitted, show the user a page that has a form in it with all of the data you want to pass on, all in hidden inputs. Just show a message like "Redirecting...". Then, add a javascript event to the page that submits the form to the third-party server.
Of the two, I would choose the second, for two reasons. First, it is more reliable than the first because Javascript is not required for it to work; for those who don't have it enabled, you can always make the submit button for the hidden form visible, and instruct them to press it if it takes more than 5 seconds. Second, you can decide what data gets transmitted to the third-party server; if you use just process the form as it goes by, you will be passing along all of the post data, which is not always what you want. Same for the 307 solution, assuming it worked for all of your users.

Hope this helps!
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予麋鹿

2020-11-22 04:33

This should make life much easier. You can simply use Response.RedirectWithData(...) method in your web application easily.

Imports System.Web
Imports System.Runtime.CompilerServices

Module WebExtensions

    <Extension()> _
    Public Sub RedirectWithData(ByRef aThis As HttpResponse, ByVal aDestination As String, _
                                ByVal aData As NameValueCollection)
        aThis.Clear()
        Dim sb As StringBuilder = New StringBuilder()

        sb.Append("<html>")
        sb.AppendFormat("<body onload='document.forms[""form""].submit()'>")
        sb.AppendFormat("<form name='form' action='{0}' method='post'>", aDestination)

        For Each key As String In aData
            sb.AppendFormat("<input type='hidden' name='{0}' value='{1}' />", key, aData(key))
        Next

        sb.Append("</form>")
        sb.Append("</body>")
        sb.Append("</html>")

        aThis.Write(sb.ToString())

        aThis.End()
    End Sub

End Module

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清酒与你

2020-11-22 04:35

Here's what I'd do :

Put the data in a standard form (with no runat="server" attribute) and set the action of the form to post to the target off-site page. Before submitting I would submit the data to my server using an XmlHttpRequest and analyze the response. If the response means you should go ahead with the offsite POSTing then I (the JavaScript) would proceed with the post otherwise I would redirect to a page on my site

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我在风中等你

2020-11-22 04:39

PostbackUrl can be set on your asp button to post to a different page.

if you need to do it in codebehind, try Server.Transfer.

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