How can a Java program get its own process ID?

Question

How do I get the id of my Java process?

I know there are several platform-dependent hacks, but I would prefer a more generic solution.

Answer 1

Try Sigar . very extensive APIs. Apache 2 license.

private Sigar sigar;

public synchronized Sigar getSigar() {
    if (sigar == null) {
        sigar = new Sigar();
    }
    return sigar;
}

public synchronized void forceRelease() {
    if (sigar != null) {
        sigar.close();
        sigar = null;
    }
}

public long getPid() {
    return getSigar().getPid();
}

Answer 2

In Scala:

import sys.process._
val pid: Long = Seq("sh", "-c", "echo $PPID").!!.trim.toLong

This should give you a workaround on Unix systems until Java 9 will be released. (I know, the question was about Java, but since there is no equivalent question for Scala, I wanted to leave this for Scala users who might stumble into the same question.)

Answer 3

This is what I used when I had similar requirement. This determines the PID of the Java process correctly. Let your java code spawn a server on a pre-defined port number and then execute OS commands to find out the PID listening on the port. For Linux

netstat -tupln | grep portNumber

Answer 4

I am adding this, in addition to other solutions.

with Java 10, to get process id

final RuntimeMXBean runtime = ManagementFactory.getRuntimeMXBean();
final long pid = runtime.getPid();
out.println("Process ID is '" + pid);

Answer 5

java.lang.management.ManagementFactory.getRuntimeMXBean().getName().split("@")[0]

Answer 6

The latest I have found is that there is a system property called sun.java.launcher.pid that is available at least on linux. My plan is to use that and if it is not found to use the JMX bean.