I have a pandas series series
. If I want to get the element-wise floor or ceiling, is there a built in method or do I have to write the function and use apply?
With Pandas, you can set a floor via clip_lower
or ceiling via clip_upper
:
s = pd.Series([-1, 0, -5, 3])
print(s.clip_lower(0))
# 0 0
# 1 0
# 2 0
# 3 3
# dtype: int64
print(s.clip_upper(0))
# 0 -1
# 1 0
# 2 -5
# 3 0
# dtype: int64
pd.Series.clip
supports more generalised functionality, e.g. applying and flooring a ceiling simultaneously, e.g. s.clip(-1, 1)
.
UPDATE: THIS ANSWER IS WRONG, DO NOT DO THIS
Explanation: using
Series.apply()
with a native vectorized Numpy function makes no sense in most cases as it will run the Numpy function in a Python loop, leading to much worse performance. You'd be much better off usingnp.floor(series)
directly, as suggested by several other answers.
You could do something like this using NumPy's floor, for instance, with a dataframe
:
floored_data = data.apply(np.floor)
Can't test it right now but an actual and working solution might not be far from it.
You can use NumPy's built in methods to do this: np.ceil(series)
or np.floor(series)
.
Both return a Series object (not an array) so the index information is preserved.
I am the OP, but I tried this and it worked:
np.floor(series)