How to use PHP in_array with associative array?

Question

Is there any php function such as in_array for associative arrays you get by the mysql function \"mysql_fetch assoc\" ?

For example, if I have an $array that looks l

Answer 1

The sample formule, using class and methods:

class VerifyInArray
{
 public function getMyCollection($field, $collection)
 {
     $list = array();
     if (count($collection)) {
        foreach ($collection as $k => $val) {
            $list[] = $val[$field];
        }
     }
     return $list;
 }

public function inMyArray($collection, $field, $findValue)
{
    if (isset($collection[0])) {
        if (array_key_exists($field, $collection[0]) == false) {
           return 'no'; 
        }
    }

    if (in_array($findValue, $this->getMyCollection($field, $collection))) {
        return 'ok';
    }
    return 'no';
}

public function displayInArray($collection, $attr, $value)
{
   return 'search result: '. $this->inMyArray($collection, $attr, $value);
}

}
$src = new VerifyInArray();

 $collection = array(
         array(
               'ID' => 1, 
               'name' => 'Smith'
         ), 
         array(
               'ID' => 2, 
               'name' => 'John'
         )
    );
echo $src->displayInArray($collection, 'ID', 2). "\n<br>" .
     $src->displayInArray($collection, 'ID', 0);

Model in ideone

Answer 2

You can't do it directly on nested arrays.. You need to nest it down a bit and then do it.

<?php
$arr=array(0=>array('ID'=>1, 'name'=>"Smith"), 1=>array('ID'=>2, 'name'=>"John"));

foreach($arr as $arr1)
{
    if(in_array(1,$arr1))
    {
       echo "Yes found.. and the correspoding key is ".key($arr1)." and the employee is ".$arr1['name'];
    }
}

OUTPUT :

Yes found.. and the correspoding key is ID and the employee is Smith

Answer 3

First you must know which part of the associative array you're going to use as haystack in in_array function. Then you can use in_array without additional code.

Example with values :

<?php
$assoc = array(1 => "apple", 2 => "banana", 3 => "lemon", 4 => "pear");
$haystack = array_values($assoc);
echo "<p>" . print_r($assoc, true) . "</p>";

$needle = 'banana';
$find = (in_array($needle, $haystack)) ? 'TRUE' : 'FALSE';
echo "<p>$needle : $find</p>";

$needle = 'cherry';
$find = (in_array($needle, $haystack)) ? 'TRUE' : 'FALSE';
echo "<p>$needle : $find</p>";
?>

Results in :

Array ( [1] => apple [2] => banana [3] => lemon [4] => pear )

banana : TRUE

cherry : FALSE

Answer 4

In your case, I wonder if simply using isset() makes more sense, i.e.

isset($a[$key])

Answer 5

Here is a one liner you can use.

$isInArray = in_array(1, array_column($names, 'ID'));

Answer 6

Try this..... You can use this function for any depth of the associated array. Just contraint to this function is that the key value would not be repeat any where in array.

<?php 
function is_in_array($array, $key, $key_value){
      $within_array = 'no';
      foreach( $array as $k=>$v ){
        if( is_array($v) ){
            $within_array = is_in_array($v, $key, $key_value);
            if( $within_array == 'yes' ){
                break;
            }
        } else {
                if( $v == $key_value && $k == $key ){
                        $within_array = 'yes';
                        break;
                }
        }
      }
      return $within_array;
}
$test = array(
                0=> array('ID'=>1, 'name'=>"Smith"), 
                1=> array('ID'=>2, 'name'=>"John")
        );
print_r(is_in_array($test, 'name', 'Smith'));
?>