How to split a byte string into separate bytes in python

Question

Ok so I\'ve been using python to try create a waveform image and I\'m getting the raw data from the .wav file using song = wave.open() and so

Answer 1

You can use slicing on byte objects:

>>> value = b'\x00\x01\x00\x02\x00\x03'
>>> value[:2]
b'\x00\x01'
>>> value[2:4]
b'\x00\x02'
>>> value[-2:]
b'\x00\x03'

When handling these frames, however, you probably also want to know about memoryview() objects; these let you interpret the bytes as C datatypes without any extra work on your part, simply by casting a 'view' on the underlying bytes:

>>> mv = memoryview(value).cast('H')
>>> mv[0], mv[1], mv[2]
256, 512, 768

The mv object is now a memory view interpreting every 2 bytes as an unsigned short; so it now has length 3 and each index is an integer value, based on the underlying bytes.

Answer 2

Here is a way that you can split the bytes into a list:

data = b'\x00\x00\x00\x00\x00\x00'
info = [data[i:i+2] for i in range(0, len(data), 2)]
print info

gives the result:

['\x00\x00', '\x00\x00', '\x00\x00']

Answer 3

You are actually asking about serialization/deserialization. Use struct.pack and struct.unpack (https://docs.python.org/3/library/struct.html). This gives you nice primitives to do both unpacking and things like endian swapping. For example:

import struct
struct.unpack("<H",b"\x00\x01") # unpacks 2 byte little endian unsigned int
struct.unpack(">l",b"\x00\x01\x02\x03") # unpacks 4 byte big endian signed int

Note that your example splits 2 byte words, not bytes.

Since this question is also coming up in searches about splitting binary strings:

value = b'\x00\x01\x00\x02\x00\x03'
split = [value[i] for i in range (0, len(value))]
# now you can modify, for example:
split[1] = 5
# put it back together
joined = bytes(split)