After calling fork,the current process will call exit(0)
.
But the child will continue.
switch(fork())
{
case -1:
exit(1);
case 0
Look at this. Use:
set follow-fork-mode <mode>
Set the debugger response to a program call of fork or vfork. A call to fork or vfork creates a new process. The <mode>
argument can be:
parent
: The original process is debugged after a fork. The child process runs unimpeded. This is the default.
child
: The new process is debugged after a fork. The parent process runs unimpeded.