Assign only if condition is true in ternary operator in JavaScript

Question

Is it possible to do something like this in JavaScript?

max = (max < b) ? b;

In other words, assign value only if the condition is true.

Answer 1

There was no example of ES6, we can use in this way:

let list = [{id: "abc", name: "test1"}, {id: "xyz", name: "test2"}]
let selectedData = {};
      list.some((exp) => {
        return (
          exp.id == "xyz" &&
          ((selectedData = exp), true)
        );
      })
console.log(selectedData);

Answer 2

I think a better approach could be

max = Math.max(max, b)

Answer 3

There isn't a specific operator that isn't the ternary operator, but you can use it like this:

max = (max < b) ? b : max;

Answer 4

I think ternary is more suitable try this

(max < b) ? max = b : '';

Answer 5

you can try:

(max < b) && (max = b);

look at this example:

let max = 10;
let b = 15;
(max < b) && (max = b)// this will be true
console.log("max=", max);

let maxx = 10
let bb = 5;
(maxx < bb) && (maxx = bb)// this will be false
console.log("maxx=", maxx);

Answer 6

You can do something like this:

(max < b) ? max = b : ''