How to get cumulative sum

Question

declare  @t table
    (
        id int,
        SomeNumt int
    )

insert into @t
select 1,10
union
select 2,12
union
select 3,3
union
select 4,15
union
select 5,23         


        

Answer 1

Select *, (Select SUM(SOMENUMT) From @t S Where S.id <= M.id) From @t M

Answer 2

For Ex: IF you have a table with two columns one is ID and second is number and wants to find out the cumulative sum.

SELECT ID,Number,SUM(Number)OVER(ORDER BY ID) FROM T

Answer 3

Try this:

CREATE TABLE #t(
 [name] varchar NULL,
 [val] [int] NULL,
 [ID] [int] NULL
) ON [PRIMARY]

insert into #t (id,name,val) values
 (1,'A',10), (2,'B',20), (3,'C',30)

select t1.id, t1.val, SUM(t2.val) as cumSum
 from #t t1 inner join #t t2 on t1.id >= t2.id
 group by t1.id, t1.val order by t1.id

Answer 4

For SQL Server 2012 onwards it could be easy:

SELECT id, SomeNumt, sum(SomeNumt) OVER (ORDER BY id) as CumSrome FROM @t

because ORDER BY clause for SUM by default means RANGE UNBOUNDED PRECEDING AND CURRENT ROW for window frame ("General Remarks" at https://msdn.microsoft.com/en-us/library/ms189461.aspx)