Since I believe this should be a basic question I know this question has probably been asked, but I am unable to find it. I\'m probably about to earn my Peer Pressure badge,
SELECT c.* FROM(
SELECT '071235' AS token UNION ALL SELECT '07113'
UNION ALL SELECT '071343'
UNION ALL SELECT '0713SA'
UNION ALL SELECT '071443') AS c
JOIN (
SELECT '0712%' AS pattern UNION ALL SELECT '0711%'
UNION ALL SELECT '071343') AS d
ON c.token LIKE d.pattern
071235
07113
071343
I had a similar goal - and came to this solution:
select *
from jobdetails as JD
where not exists ( select code from table_of_codes as TC
where JD.job_no like TC.code )
I'm assuming that your various codes ('0711%', '0712%', etc), including the %, are stored in a table, which I'm calling *table_of_codes*, with field code.
If the % is not stored in the table of codes, just concatenate the '%'. For example:
select *
from jobdetails as JD
where not exists ( select code from table_of_codes as TC
where JD.job_no like concat(TC.code, '%') )
The concat() function may vary depending on the particular database, as far as I know.
I hope that it helps. I adapted it from:
http://us.generation-nt.com/answer/subquery-wildcards-help-199505721.html
How about:
WHERE LEFT(job_no, 4) IN ('0711', '0712', ...)
I think I have a solution to what the originator of this inquiry wanted in simple form. It works for me and actually it is the reason I came on here to begin with. I believe just using parentheses around the column like '%text%' in combination with OR
s will do it.
select * from tableName
where (sameColumnName like '%findThis%' or sameColumnName like '%andThis%' or
sameColumnName like '%thisToo%' or sameColumnName like '%andOneMore%')
You could try something like this:
select *
from jobdetails
where job_no like '071[12]%'
Not exactly what you're asking, but it has the same effect, and is flexible in other ways too :)
In Access SQL, I would use this. I'd imagine that SQLserver has the same syntax.
select * from jobdetails where job_no like "0711*" or job_no like "0712*"