Converting string to tuple without splitting characters

Question

I am striving to convert a string to a tuple without splitting the characters of the string in the process. Can somebody suggest an easy method to do this. Need a one liner.

Answer 1

This only covers a simple case:

a = ‘Quattro TT’
print tuple(a)

If you use only delimiter like ‘,’, then it could work.

I used a string from configparser like so:

list_users = (‘test1’, ‘test2’, ‘test3’)
and the i get from file
tmp = config_ob.get(section_name, option_name)
>>>”(‘test1’, ‘test2’, ‘test3’)”

In this case the above solution does not work. However, this does work:

def fot_tuple(self, some_str):
     # (‘test1’, ‘test2’, ‘test3’)
     some_str = some_str.replace(‘(‘, ”)
     # ‘test1’, ‘test2’, ‘test3’)
     some_str = some_str.replace(‘)’, ”)
     # ‘test1’, ‘test2’, ‘test3’
     some_str = some_str.replace(“‘, ‘”, ‘,’)
     # ‘test1,test2,test3’
     some_str = some_str.replace(“‘”, ‘,’)
     # test1,test2,test3
     # and now i could convert to tuple
     return tuple(item for item in some_str.split(‘,’) if item.strip())

Answer 2

See:

'Quattro TT'

is a string.

Since string is a list of characters, this is the same as

['Q', 'u', 'a', 't', 't', 'r', 'o', ' ', 'T', 'T']

Now...

['Quattro TT']

is a list with a string in the first position.

Also...

a = 'Quattro TT'

list(a)

is a string converted into a list.

Again, since string is a list of characters, there is not much change.

Another information...

tuple(something)

This convert something into tuple.

Understanding all of this, I think you can conclude that nothing fails.

Answer 3

I use this function to convert string to tuple

import ast

def parse_tuple(string):
    try:
        s = ast.literal_eval(str(string))
        if type(s) == tuple:
            return s
        return
    except:
        return

Usage

parse_tuple('("A","B","C",)')  # Result: ('A', 'B', 'C')

In your case, you do

value = parse_tuple("('%s',)" % a)