Efficient way to convert strings from split function to ints in Python

Question

I have a string of data with the following format: xpos-ypos-zoom (i.e. 8743-12083-15) that I want to split up and store in the variables xpos, ypos, and zoom. Since I need

Answer 1

efficient as in fewer lines of code?

(xval,yval,zval) = [int(s) for s in file.split('-')]

Answer 2

My original suggestion with a list comprehension.

test = '8743-12083-15'
lst_int = [int(x) for x in test.split("-")]

EDIT:

As to which is most efficient (cpu-cyclewise) is something that should always be tested. Some quick testing on my Python 2.6 install indicates map is probably the most efficient candidate here (building a list of integers from a value-splitted string). Note that the difference is so small that this does not really matter until you are doing this millions of times (and it is a proven bottleneck)...

def v1():
 return [int(x) for x in '8743-12083-15'.split('-')]

def v2():
 return map(int, '8743-12083-15'.split('-'))

import timeit
print "v1", timeit.Timer('v1()', 'from __main__ import v1').timeit(500000)
print "v2", timeit.Timer('v2()', 'from __main__ import v2').timeit(500000)

> output v1 3.73336911201 
> output v2 3.44717001915

Answer 3

You can map the function int on each substring, or use a list comprehension:

>>> file = '8743-12083-15'
>>> list(map(int, file.split('-')))
[8743, 12083, 15]
>>> [int(d) for d in file.split('-')]
[8743, 12083, 15]

In the above the call to list is not required, unless working with Python 3.x. (In Python 2.x map returns a list, in Python 3.x it returns a generator.)

Directly assigning to the three variables is also possible (in this case a generator expression instead of a list comprehension will do):

>>> xval, yval, zval = (int(d) for d in file.split('-'))
>>> xval, yval, zval
(8743, 12083, 15)

Answer 4

note: you might want to pick a different name for file as it shadows the buildtin

this works in Python 2 and 3

xval,yval,zval = map(int,file.split('-'))