I am making an Order
model for a shopping cart and I need to make a field that auto increments when the order is made:
class Order(models.Model)
Edited: Fixed mistake in code that stopped it working if there were no
YourModel
entries in the db.
There's a lot of mention of how you should use an AutoField, and of course, where possible you should use that.
However there are legitimate reasons for implementing auto-incrementing fields yourself (such as if you need an id to start from 500 or increment by tens for whatever reason).
In your models.py
from django.db import models
def from_500():
'''
Returns the next default value for the `ones` field,
starts from 500
'''
# Retrieve a list of `YourModel` instances, sort them by
# the `ones` field and get the largest entry
largest = YourModel.objects.all().order_by('ones').last()
if not largest:
# largest is `None` if `YourModel` has no instances
# in which case we return the start value of 500
return 500
# If an instance of `YourModel` is returned, we get it's
# `ones` attribute and increment it by 1
return largest.ones + 1
def add_ten():
''' Returns the next default value for the `tens` field'''
# Retrieve a list of `YourModel` instances, sort them by
# the `tens` field and get the largest entry
largest = YourModel.objects.all().order_by('tens').last()
if not largest:
# largest is `None` if `YourModel` has no instances
# in which case we return the start value of 10
return 10
# If an instance of `YourModel` is returned, we get it's
# `tens` attribute and increment it by 10
return largest.tens + 10
class YourModel(model.Model):
ones = models.IntegerField(primary_key=True,
default=from_500)
tens = models.IntegerField(default=add_ten)
You can use default primary key (id) which auto increaments.
Note: When you use first design i.e. use default field (id) as a primary key, initialize object by mentioning column names. e.g.
class User(models.Model):
user_name = models.CharField(max_length = 100)
then initialize,
user = User(user_name="XYZ")
if you initialize in following way,
user = User("XYZ")
then python will try to set id = "XYZ" which will give you error on data type.
In Django
1 : we have default field with name "id" which is auto increment.
2 : You can define a auto increment field using AutoField
field.
class Order(models.Model): auto_increment_id = models.AutoField(primary_key=True) #you use primary_key = True if you do not want to use default field "id" given by django to your model
+------------+---------------------------------------------------------------------------------------------------------------------------------------------------------------+ | Table | Create Table | +------------+---------------------------------------------------------------------------------------------------------------------------------------------------------------+ | core_order | CREATE TABLE `core_order` ( `auto_increment_id` int(11) NOT NULL AUTO_INCREMENT, PRIMARY KEY (`auto_increment_id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 | +------------+---------------------------------------------------------------------------------------------------------------------------------------------------------------+ 1 row in set (0.01 sec)
class Order(models.Model): dd_date = models.DateTimeField(auto_now_add=True)
+-------------+-----------------------------------------------------------------------------------------------------------------------------------------------------------------+ | Table | Create Table | +-------------+-----------------------------------------------------------------------------------------------------------------------------------------------------------------+ | core_order | CREATE TABLE `core_order` ( `id` int(11) NOT NULL AUTO_INCREMENT, `dd_date` datetime NOT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 | +-------------+-----------------------------------------------------------------------------------------------------------------------------------------------------------------+
You can create an autofield. Here is the documentation for the same
Please remember Django won't allow to have more than one AutoField in a model, In your model you already have one for your primary key (which is default). So you'll have to override model's save method and will probably fetch the last inserted record from the table and accordingly increment the counter and add the new record.
Please make that code thread safe because in case of multiple requests you might end up trying to insert same value for different new records.
What I needed: A document number with a fixed number of integers that would also act like an AutoField
.
My searches took me all over incl. this page.
Finally I did something like this:
I created a table with a DocuNumber
field as an IntegerField with foll. attributes:
max_length=6
primary_key=True
unique=True
default=100000
The max_length
value anything as required (and thus the corresponding default=
value).
A warning is issued while creating the said model, which I could ignore.
Afterwards, created a document (dummy) whence as expected, the document had an integer field value of 100000.
Afterwards changed the model key field as:
AutoField
max_length
And default
attributesprimary_key = True
attributeThe next (desired document) created had the value as 100001 with subsequent numbers getting incremented by 1.
So far so good.
class Belly(models.Model):
belly_id = models.AutoField(primary_key=True)
belly_name = models.CharField(max_length=50)
******** or *******
class Belly(models.Model):
belly_name = models.CharField(max_length=50)
The difference is:
The first table has the primary key belly_id
(specified as AutoField
) and second table has the primary key id
(implicitly).
I think no need to use this directly; a primary key field will automatically be added to your model if you don’t specify. Otherwise
Check the Django Documentation for AutoField for further details related to AutoField
.