Checking whether a variable is an integer or not [duplicate]

Answer 1

Found a related question here on SO itself.

Python developers prefer to not check types but do a type specific operation and catch a TypeError exception. But if you don't know the type then you have the following.

>>> i = 12345
>>> type(i)
<type 'int'>
>>> type(i) is int
True

Answer 2

use the int function to help

intchecker = float(input('Please enter a integer: '))
intcheck = 0
while intcheck != 1:
    if intchecker - int(intchecker) > 0:
        intchecker = float(input("You didn't enter a integer. "
                                 "Please enter a integer: "))
    else:
        intcheck = 1
print('you have entered a integer')

Answer 3

A simple way to do this is to directly check if the remainder on division by 1 is 0 or not.

if this_variable % 1 == 0:
    list.append(this_variable)
else:
    print 'Not an Integer!'

Answer 4

You can do this.

if type(x) is int:

Answer 5

If you have not int you can do just this:

var = 15.4
if(var - int(var) != 0):
    print "Value is not integer"

Answer 6

#######################################
# Value_Is_Int
#######################################
def value_is_int(value):
    try:
        tempVal = int(value)
        return True
    except:
        return False

Call this function:

if value_is_int(value):
    print "Integer"
else:
    print "Not integer"