Add php variable inside echo statement as href link address?

Question

I\'m trying to use a php variable to add a href value for a link in an echo statement.

Here\'s a simplified version of the code I want to use. I know that I can\'t j

Answer 1

as simple as that: echo '<a href="'.$link_address.'">Link</a>';

Answer 2

Try like

HTML in PHP :

echo "<a href='".$link_address."'>Link</a>";

Or even you can try like

echo "<a href='$link_address'>Link</a>";

Or you can use PHP in HTML like

PHP in HTML :

<a href="<?php echo $link_address;?>"> Link </a>

Answer 3

you can either use

echo '<a href="'.$link_address.'">Link</a>';

or

echo "<a href=\"$link_address\">Link</a>';

if you use double quotes you can insert the variable into the string and it will be parsed.

Answer 4

If you want to print in the tabular form with, then you can use this:

echo "<tr> <td><h3> ".$cat['id']."</h3></td><td><h3> ".$cat['title']."<h3></</td><td> <h3>".$cat['desc']."</h3></td><td><h3> ".$cat['process']."%"."<a href='taskUpdate.php' >Update</a>"."</h3></td></tr>" ;

Answer 5

Basically like this,

<?php
$link = ""; // Link goes here!
print "<a href="'.$link.'">Link</a>";
?>