I\'ve already gone through question
I understand that, it is necessary to implement ==
, !=
and Equals()
.
publ
As Selman22 said, you are overriding the default object.Equals
method, which accepts an object obj
and not a safe compile time type.
In order for that to happen, make your type implement IEquatable<Box>:
public class Box : IEquatable<Box>
{
double height, length, breadth;
public static bool operator ==(Box obj1, Box obj2)
{
if (ReferenceEquals(obj1, obj2))
{
return true;
}
if (ReferenceEquals(obj1, null))
{
return false;
}
if (ReferenceEquals(obj2, null))
{
return false;
}
return obj1.Equals(obj2);
}
public static bool operator !=(Box obj1, Box obj2)
{
return !(obj1 == obj2);
}
public bool Equals(Box other)
{
if (ReferenceEquals(other, null))
{
return false;
}
if (ReferenceEquals(this, other))
{
return true;
}
return height.Equals(other.height)
&& length.Equals(other.length)
&& breadth.Equals(other.breadth);
}
public override bool Equals(object obj)
{
return Equals(obj as Box);
}
public override int GetHashCode()
{
unchecked
{
int hashCode = height.GetHashCode();
hashCode = (hashCode * 397) ^ length.GetHashCode();
hashCode = (hashCode * 397) ^ breadth.GetHashCode();
return hashCode;
}
}
}
Another thing to note is that you are making a floating point comparison using the equality operator and you might experience a loss of precision.
I think you declared the Equals
method like this:
public override bool Equals(BOX obj)
Since the object.Equals
method takes an object, there is no method to override with this signature. You have to override it like this:
public override bool Equals(object obj)
If you want type-safe Equals,
you can implement IEquatable<BOX>
.
In fact, this is a "how to" subject. So, here is the reference implementation:
public class BOX
{
double height, length, breadth;
public static bool operator == (BOX b1, BOX b2)
{
if ((object)b1 == null)
return (object)b2 == null;
return b1.Equals(b2);
}
public static bool operator != (BOX b1, BOX b2)
{
return !(b1 == b2);
}
public override bool Equals(object obj)
{
if (obj == null || GetType() != obj.GetType())
return false;
var b2 = (BOX)obj;
return (length == b2.length && breadth == b2.breadth && height == b2.height);
}
public override int GetHashCode()
{
return height.GetHashCode() ^ length.GetHashCode() ^ breadth.GetHashCode();
}
}
REF: https://msdn.microsoft.com/en-us/library/336aedhh(v=vs.100).aspx#Examples
UPDATE: the cast to (object)
in the operator ==
implementation is important, otherwise, it would re-execute the operator == overload, leading to a stackoverflow. Credits to @grek40.
This (object)
cast trick is from Microsoft String
== implementaiton.
SRC: https://github.com/Microsoft/referencesource/blob/master/mscorlib/system/string.cs#L643
public class BOX
{
double height, length, breadth;
public static bool operator == (BOX b1, BOX b2)
{
if (b1 is null)
return b2 is null;
return b1.Equals(b2);
}
public static bool operator != (BOX b1, BOX b2)
{
return !(b1 == b2);
}
public override bool Equals(object obj)
{
if (obj == null)
return false;
return obj is BOX b2? (length == b2.length &&
breadth == b2.breadth &&
height == b2.height): false;
}
public override int GetHashCode()
{
return (height,length,breadth).GetHashCode();
}
}