Calculating Time Difference

Question

at the start and end of my program, I have

from time import strftime
print int(strftime(\"%Y-%m-%d %H:%M:%S\")



Y1=int(strftime(\"%Y\"))
m1=int(strftime(\         


        

Answer 1

time.monotonic() (basically your computer's uptime in seconds) is guarranteed to not misbehave when your computer's clock is adjusted (such as when transitioning to/from daylight saving time).

>>> import time
>>>
>>> time.monotonic()
452782.067158593
>>>
>>> a = time.monotonic()
>>> time.sleep(1)
>>> b = time.monotonic()
>>> print(b-a)
1.001658110995777

Answer 2

Here is a piece of code to do so:

def(StringChallenge(str1)):

#str1 = str1[1:-1]
h1 = 0
h2 = 0
m1 = 0
m2 = 0

def time_dif(h1,m1,h2,m2):
    if(h1 == h2):
        return m2-m1
    else:
        return ((h2-h1-1)*60 + (60-m1) + m2)
count_min = 0

if str1[1] == ':':
    h1=int(str1[:1])
    m1=int(str1[2:4])
else:
    h1=int(str1[:2])
    m1=int(str1[3:5])

if str1[-7] == '-':
    h2=int(str1[-6])
    m2=int(str1[-4:-2])
else:
    h2=int(str1[-7:-5])
    m2=int(str1[-4:-2])

if h1 == 12:
    h1 = 0
if h2 == 12:
    h2 = 0

if "am" in str1[:8]:
    flag1 = 0
else:
    flag1= 1

if "am" in str1[7:]:
    flag2 = 0
else:
    flag2 = 1

if flag1 == flag2:
    if h2 > h1 or (h2 == h1 and m2 >= m1):
        count_min += time_dif(h1,m1,h2,m2)
    else:
        count_min += 1440 - time_dif(h2,m2,h1,m1)
else:
    count_min += (12-h1-1)*60
    count_min += (60 - m1)
    count_min += (h2*60)+m2


return count_min

Answer 3

The datetime module will do all the work for you:

>>> import datetime
>>> a = datetime.datetime.now()
>>> # ...wait a while...
>>> b = datetime.datetime.now()
>>> print(b-a)
0:03:43.984000

If you don't want to display the microseconds, just use (as gnibbler suggested):

>>> a = datetime.datetime.now().replace(microsecond=0)
>>> b = datetime.datetime.now().replace(microsecond=0)
>>> print(b-a)
0:03:43

Answer 4

You cannot calculate the differences separately ... what difference would that yield for 7:59 and 8:00 o'clock? Try

import time
time.time()

which gives you the seconds since the start of the epoch.

You can then get the intermediate time with something like

timestamp1 = time.time()
# Your code here
timestamp2 = time.time()
print "This took %.2f seconds" % (timestamp2 - timestamp1)

Answer 5

from time import time

start_time = time()
...

end_time = time()
seconds_elapsed = end_time - start_time

hours, rest = divmod(seconds_elapsed, 3600)
minutes, seconds = divmod(rest, 60)